Skip to main content

How to remove all of the memory used by Mathematica


Backgroud


When I create the notebook,it will be made mess by me sometimes.If I use Remove to remove those variables,the memory cannot release still.So I have to close this mess notebook and restart the MMA to create another new notebook.I want to find way by programal method to avoid restarting the MMA,which can remove all of the variable and can release the memory.




Test code:


In[1]:= memory := Row[{"Memory Used:", MemoryInUse[]/1024^2., " MB"}];

memory
Out[2]= Memory Used:99.3511 MB

In[3]:= a = RandomReal[1, 20000000];
memory
Out[4]= Memory Used:255.345 MB

As we see,the value of memory used by Mathematica currently is $255.345MB$.How to release it and make it back to $99.3511M$?As I try,the ClearAll,Remove and ClearSystemCache cannot do this.




Update: As this answer,I change the test code to be following:



In[1]:= c`memory :=Row[{"Memory Used:", MemoryInUse[]/1024^2., " MB"}];
c`memory
Out[2]= Memory Used:58.117 MB

In[3]:= a = RandomReal[1, 20000000];
c`memory
Out[4]= Memory Used:216.487 MB

In[5]:= Unprotect[In, Out];
Clear[In, Out]

Quiet[Remove["`*"]]
$Line = 0;

In[1]:= c`memory
Out[1]= Memory Used:63.2716 MB

The last output is $63-58=5M$ lager than first output still.How to release it?



Answer



As Szabolcs wrote in this great answer, there are, from the old days, two functions that are meant to restore the kernel to its former state and recover as much memory as possible without having to restart it.


Try this on a fresh kernel:



memory := Row[{"Memory Used:", MemoryInUse[]/1024^2., " MB"}];
Needs["Utilities`CleanSlate`"]
memory
a = RandomReal[1, 20000000];
memory
CleanSlate[];
ClearInOut[];
memory

Mathematica graphics



All memory was recovered. Note that it only resets definitions that were made after the package was loaded, therefore in this case it didn't reset the definition for memory.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...