When I try to solve, the following equation over the integers using WolframAlpha:
$$x^2(1+x)=y(3y-1)\tag1$$
WolframAlpha gives me the following solutions $(x,y)$:
$$(-1,0),(0,0),(1,1),(4,-5),(6,-9)\tag2$$
Is WolframAlpha giving me all the solutions? Or can there be more?
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