Skip to main content

import - Plotting data with exponentials


I have some data with 19000 sublists such as :


{"   7.9080000e+01   1.9283193e+04"}

Where the first number is the value for variable A and the second for variable B.


All my attempts to transform this format have failed so far. I think my best guess was using ToExpression unsuccessfully.


How can I transform such lists to a "plottable" format by



  • Changing the String format ?


  • Computing the e ?

  • Import the data differently ?



Answer



You should be able to use ReadList on the string contents of each sublist. Here I'm just creating a small list containing three elements identical to the one you provided. The result can be plotted using ListPlot for example.


In[20]:= in = {{"   7.9080000e+01   1.9283193e+04"}, 
{" 7.9080000e+01 1.9283193e+04"},
{" 7.9080000e+01 1.9283193e+04"}};

In[22]:= Table[ReadList[StringToStream@First[i], Number], {i, in}]


Out[22]= {{79.08, 19283.2}, {79.08, 19283.2}, {79.08, 19283.2}}

EDIT:


Due to the comments I should point out that this Table is going to produce an array that is not packed. This means that the evaluator isn't aware ahead of time that all of the values are a particular type (namely real in this case) and so it is going to lean toward more general methods and is going to consume more memory to store the table.


As the documentation for Developer`ToPackedArray points out, using Developer`ToPackedArray will not change results generated by Mathematica, but can enhance speed of execution and reduce memory usage.


In order to pack the result we can simply use ruebenko's suggestion placing Developer`ToPackedArray@ in front of our Table.


TESTING EDIT:


I decided to test whether ImportString proposed by Mr. Wizard or the ReadList approach might be faster. In fairness I separated the ExportString out presuming that the string would already be saved somewhere for importing. It appears that ReadList is much faster at least for the fabricated example I've created here. I'd be curious to see if this is true for 500's data.


In[21]:= data = Table["   7.9080000e+01   1.9283193e+04", {5000}];


In[22]:= Export["numbers.txt", data];

In[23]:= in = Partition[ReadList[StringToStream@Import["numbers.txt",
"Plaintext"], Record], 1];

In[24]:= (andyr = Table[ReadList[StringToStream@First[i], Number]
, {i, in}]); // AbsoluteTiming

Out[24]= {0.0780015, Null}


In[25]:= str = ExportString[in, "Table"];

In[26]:= (mrwiz = ImportString[str, "Table"]); // AbsoluteTiming

Out[26]= {4.1340795, Null}

In[27]:= andyr === mrwiz

Out[27]= True


I should also point out that this comparison is only fair if we assume that the data is already in memory. If not, the cost for Importing should be factored in to the ReadList approach.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.