Skip to main content

differential equations - DSolve doesn't find a solution



I have this partial differential equation (G and M are constants):


enter image description here


and a solution is:


enter image description here


Mathematica doesn't find any solutions. My code for DSolve is:


DSolve[-2*G*M^2*r*Derivative[0, 2][γ][r, z] + 2*G*M^2*Derivative[1, 0][γ][r, z] + 
2*G*M^2*r*Derivative[2, 0][γ][r, z] == 0, γ[r, z], {r, z}]

and as a result I just got an echo:


enter image description here



Any suggestions? Or nothing can be done in this case?



Answer



Since there doesn't seem to be an easy automated way of solving this partial differential equation in general, it may be worth asking at least for the minimum of manual work required to get a solution. I'll omit the various common constants in the original differential equation because they can be divided out.


From the equation it is pretty obvious that we should expect separation of variables to work (the particular solution g = r^2 + 2z^2 in the question is not of this type, but since there are no boundary conditions specified it seems we should find a set of general solutions). Therefore, I'll guide Mathematica to obtain the separated equations for the z and r coordinates:


ClearAll[γ]

equations = -r*Derivative[0, 2][γ][r, z] +
Derivative[1, 0][γ][r, z] +
r*Derivative[2, 0][γ][r, z] == 0



$r \,\text{g2}(z) \text{g1}''(r)+\text{g2}(z) \text{g1}'(r)-r \,\text{g1}(r) \text{g2}''(z)=0$



γ[r_, z_] := g1[r] g2[z]

separatedEqn = Simplify[Map[#/(r g1[r] g2[z]) &, equations], r > 0]


$\frac{\text{g1}''(r)+\frac{\text{g1}'(r)}{r}} {\text{g1}(r)}=\frac{\text{g2}''(z)}{\text {g2}(z)}$




γ[r, z] /. 
Flatten@{DSolve[separatedEqn[[1]] == K, g1, r,
GeneratedParameters -> CR],
DSolve[separatedEqn[[2]] == K, g2, z, GeneratedParameters -> CZ]}


$\left(\text{CZ}(1) e^{\sqrt{K} z}+\text{CZ}(2) e^{-\sqrt{K} z}\right) \left(\text{CR}(1) J_0\left(i \sqrt{K} r\right)+\text{CR}(2) Y_0\left(-i \sqrt{K} r\right)\right)$



Here, K is the separation constant which has to be set equal to the left and right-hand side of separatedEqn by the standard argument of the separation technique: each side manifestly depends only on one of the two independent variables (r or z), and therefore both sides must be equal to a common constant.


The resulting ordinary differential equations with z and r as variables can then be solved with DSolve, leading to four additional integration constants. Since I want to combine the solutions for the factors g1[r] and g2[z], I have to make sure to use different names for the integration constants, which is done using GeneratedParameters.



Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...