plotting - Drawing the Pursuit curves

I was reading this post on Filling Space with Pursuit Polygons. I didn't really see where the filling was, but found it quite interesting.

Then I saw these pursuit curves.

They seem to have used a different logarithm. For example looking at the square, by tweaking the code from the previous code, I got this

With[{data = {{0, 0}, {1, 0}, {1, 1}, {0, 1}, {0, 0}}},  Graphics[{Table[{Scale[       Rotate[Line[data], 90/11*x Degree], {x, x}]}, {x, 0, 11}]}]]

Both picture has 11 sets of squares. With a bit trial and error, I got as close as possible by changing the angles.

How can I get the identical pictures?

And these ones below, which looks more challenging.

Answer

In this answer of mine I wrote a simple function that will draw the curve you are after, given an arbitrary polygon:

g[x_] := Fold[Append[#1, BSplineFunction[#1[[#2]], SplineDegree -> 1][.1]] &, x, Partition[Range[200], 2, 1]]

For example, given the triangle

ListPlot[Prepend[{{0, 0}, {1, 0}, {1/2, Sqrt[3]/2}}, {1/2, Sqrt[3]/2}], AspectRatio -> 1, Joined -> True, PlotRange -> All]

we get

ListPlot[Prepend[g@{{0, 0}, {1, 0}, {1/2, Sqrt[3]/2}}, {1/2, Sqrt[3]/2}], AspectRatio -> 1, Joined -> True, PlotRange -> All]

With this, it is just a matter of combining triangles to generate all the figures in the OP.

For example, given the hexagon

ListPlot[{Prepend[{{0, 0}, {1, 0}, {1/2, Sqrt[3]/2}}, {1/2, Sqrt[3]/2}], Prepend[{{1, 0}, {2, 0}, {3/2, Sqrt[3]/2}}, {3/2, Sqrt[3]/2}], Prepend[{{0, 0}, {1, 0}, {1/2, -(Sqrt[3]/2)}}, {1/2, -(Sqrt[3]/2)}], Prepend[{{1, 0}, {2, 0}, {3/2, -(Sqrt[3]/2)}}, {3/2, -(Sqrt[3]/2)}], Prepend[{{1/2, Sqrt[3]/2}, {3/2, Sqrt[3]/2}, {1, 0}}, {1, 0}], Prepend[{{1/2, -(Sqrt[3]/2)}, {3/2, -(Sqrt[3]/2)}, {1, 0}}, {1, 0}]}, AspectRatio -> 1, Joined -> True, PlotRange -> All]

we get

ListPlot[{Prepend[g@{{0, 0}, {1, 0}, {1/2, Sqrt[3]/2}}, {1/2, Sqrt[3]/2}], Prepend[g@{{1, 0}, {2, 0}, {3/2, Sqrt[3]/2}}, {3/2, Sqrt[3]/2}], Prepend[g@{{0, 0}, {1, 0}, {1/2, -(Sqrt[3]/2)}}, {1/2, -(Sqrt[3]/2)}], Prepend[g@{{1, 0}, {2, 0}, {3/2, -(Sqrt[3]/2)}}, {3/2, -(Sqrt[3]/2)}], Prepend[g@{{1/2, Sqrt[3]/2}, {3/2, Sqrt[3]/2}, {1, 0}}, {1, 0}], Prepend[g@{{1/2, -(Sqrt[3]/2)}, {3/2, -(Sqrt[3]/2)}, {1, 0}}, {1, 0}]}, AspectRatio -> 1, Joined -> True, PlotRange -> All]

Tweaking the parameters and using black lines, we get

which is almost identical to the figure in the OP. Similarly,

while the rest of figures are left to the reader.