Skip to main content

Applying an ArrayPlot as a texture to the surface of a cylinder


I would like to apply a matrix plot to the surface of a 3D cylinder. The matrix plot is the output from a custom cellular-automata, and it would be nice to see the lefthand side of the plot connected to the righthand side.


Edit


This is the solution I ended up using:


mrt =
ArrayPlot[CellularAutomaton[30, RandomInteger[{0, 1}, 100], 30],

Frame -> False,
ImagePadding -> 0,
PlotRangePadding -> 0];
ParametricPlot3D[{Sin[t]/2Pi, Cos[t]/2Pi,u},{t,0,2Pi},{u,0,2},
Boxed -> False,
Axes -> False,
PerformanceGoal -> "Quality",
ImageSize -> {300, 300},
Lighting -> "Neutral",
PlotStyle -> Texture[mrt],

Mesh -> None,
ViewPoint -> {0, 3, 1}]

enter image description here



Answer



You can use the raster image produced by MatrixPlot as Texture directive if you construct Cylinder using ParametricPlot3D or ContourPlot3D.


 mplt = MatrixPlot[Table[Sin[x y/100], {x, -10, 10}, {y, -10, 10}], 
ColorFunction -> "Rainbow", Frame -> False, ImagePadding -> 0,
PlotRangePadding -> 0]


enter image description here


ParametricPlot3D


 ParametricPlot3D[{Cos[theta], Sin[theta], rho}, {theta, -Pi, Pi}, {rho, 0, 2}, 
PlotStyle -> Directive[Specularity[White, 30], Texture[mplt]],
TextureCoordinateFunction -> ({#1, #3} &), Lighting -> "Neutral",
Mesh -> None, PlotRange -> All, TextureCoordinateScaling -> True]

enter image description here


Update: To wrap the matrix plot around the cylinder


Change the setting for TextureCoordinateFunction to



TextureCoordinateFunction -> ({#4, #5} &)  (*Thanks: @Rahul *)

enter image description here


Or leave out the TextureCoordinate... options out and use PlotStyle -> Texture[mplt] (thanks: @DROP TABLE):


ParametricPlot3D[{Cos[theta], Sin[theta], rho}, {theta, -Pi, Pi}, {rho, 0, 2},
PlotStyle -> Texture[mplt], Lighting -> "Neutral", Mesh -> None,
PlotRange -> All, ImageSize -> 400]

enter image description here


ContourPlot3D



ContourPlot3D[x^2 + y^2 == 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, 
Mesh -> None, Lighting -> "Neutral",
ContourStyle -> Directive[Specularity[White, 30], Texture[mplt]],
TextureCoordinateFunction -> ({#1, #3} &)]

enter image description here


Related:


How to Texturize Disk/Circle/Rectangle


Heike's answer MathGroup: Texture on Disk in Mathematica 8


Wraping a Rectangle to Form a Cylinder



ColorFunction and ColorFunctionScaling Issue with ParametricPLot3D


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...