Skip to main content

Applying an ArrayPlot as a texture to the surface of a cylinder


I would like to apply a matrix plot to the surface of a 3D cylinder. The matrix plot is the output from a custom cellular-automata, and it would be nice to see the lefthand side of the plot connected to the righthand side.


Edit


This is the solution I ended up using:


mrt =
ArrayPlot[CellularAutomaton[30, RandomInteger[{0, 1}, 100], 30],

Frame -> False,
ImagePadding -> 0,
PlotRangePadding -> 0];
ParametricPlot3D[{Sin[t]/2Pi, Cos[t]/2Pi,u},{t,0,2Pi},{u,0,2},
Boxed -> False,
Axes -> False,
PerformanceGoal -> "Quality",
ImageSize -> {300, 300},
Lighting -> "Neutral",
PlotStyle -> Texture[mrt],

Mesh -> None,
ViewPoint -> {0, 3, 1}]

enter image description here



Answer



You can use the raster image produced by MatrixPlot as Texture directive if you construct Cylinder using ParametricPlot3D or ContourPlot3D.


 mplt = MatrixPlot[Table[Sin[x y/100], {x, -10, 10}, {y, -10, 10}], 
ColorFunction -> "Rainbow", Frame -> False, ImagePadding -> 0,
PlotRangePadding -> 0]


enter image description here


ParametricPlot3D


 ParametricPlot3D[{Cos[theta], Sin[theta], rho}, {theta, -Pi, Pi}, {rho, 0, 2}, 
PlotStyle -> Directive[Specularity[White, 30], Texture[mplt]],
TextureCoordinateFunction -> ({#1, #3} &), Lighting -> "Neutral",
Mesh -> None, PlotRange -> All, TextureCoordinateScaling -> True]

enter image description here


Update: To wrap the matrix plot around the cylinder


Change the setting for TextureCoordinateFunction to



TextureCoordinateFunction -> ({#4, #5} &)  (*Thanks: @Rahul *)

enter image description here


Or leave out the TextureCoordinate... options out and use PlotStyle -> Texture[mplt] (thanks: @DROP TABLE):


ParametricPlot3D[{Cos[theta], Sin[theta], rho}, {theta, -Pi, Pi}, {rho, 0, 2},
PlotStyle -> Texture[mplt], Lighting -> "Neutral", Mesh -> None,
PlotRange -> All, ImageSize -> 400]

enter image description here


ContourPlot3D



ContourPlot3D[x^2 + y^2 == 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, 
Mesh -> None, Lighting -> "Neutral",
ContourStyle -> Directive[Specularity[White, 30], Texture[mplt]],
TextureCoordinateFunction -> ({#1, #3} &)]

enter image description here


Related:


How to Texturize Disk/Circle/Rectangle


Heike's answer MathGroup: Texture on Disk in Mathematica 8


Wraping a Rectangle to Form a Cylinder



ColorFunction and ColorFunctionScaling Issue with ParametricPLot3D


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...