So I am trying to solve the movement in space and time of a spreading gravity current. The interface satisfies the following PDE:
∂h∂t=∂∂x(h3∂h∂x).
The nose, h(x,t)=0, of the current can move forward in space. If we say the initial condition is h(x,0)=1−x, then the nose, xN is initially at x=1. The base of the current can be fixed at h(0,t)=1. So I have one IC and one BC, I need another BC to close the system. Now, as time moves forward the nose (fixed at h = 0) propagates according to the expression:
∫xN0hdx=12+t
or kinematically ˙xN=−h2hx.
Clearly the second boundary condition in x needs to come from the nose condition, but I have no idea how to input an integral boundary condition or the kinematic condition. Secondly, I have no idea how to deal with xmax in NDSolve as clearly my xmax is moving forward with each time step.
Here is my attempt, which gives a "There are fewer dependent variables error"
NDSolve[{D[h[x, t], t] == D[h[x, t]^3 D[h[x, t], x], x], h[0, t] == 1,
h[x, 0] == 1 - x (D[h[x, t], t] /. x -> 1) == -h[x, t]^2 (D[h[x, t], x] /.
x -> 1)}, h, {x, 0, 1}, {t, 0, 1}]
EDIT
So I solved this problem by amending the code in this Stefan problem post. I modified the statement of the problem slightly to work more closely to @ybeltukov excellent solution, and actually solved the following system:
∂h∂t=∂∂x(h3∂h∂x)˙s=−h2hxs(0)=0h(x,0)={1for x=00otherwiseh(s(t),t)=0h(0,t)=1.
I made the same change to a normalised variable for my PDE and then amended finite difference code:
n = 100;
\[Delta]\[Xi] = 1./n;
ClearAll[dv, t];
dv[v_List] :=
With[{s = First@v, u = Rest@v},
With[{ds = u[[-1]]^3/(s \[Delta]\[Xi]), \[Xi] = N@Range[n - 1]/n,
d1 = ListCorrelate[{-0.5, 0, 0.5}/\[Delta]\[Xi], #] &,
d2 = ListCorrelate[{1, -2, 1}/\[Delta]\[Xi]^2, #] &},
Prepend[3 u^2 d1[#]^2/s^2 + u^3 d2[#]/s^2 + \[Xi] ds d1[#]/s &@
Join[{1}, u, {0.}], ds]]];
s0 = 0.001;
v0 = Flatten@Prepend[ConstantArray[0.001, n - 2], {s0, 1.}];
sol = NDSolve[{v'[t] == dv[v[t]], v[0] == v0}, v, {t, 0, 50}][[1, 1,
2]];
Returning from the normalised variable is identical code.
You can then make a nice time series with this code:
ListAnimate[
Table[Plot[u[t, x], {x, 0, 10}, PlotRange -> {{0, 10}, {0, 3}}], {t,
0, 50, 0.1}]]
Which returns a spreading current as desired.
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