Skip to main content

polynomials - Decomposition of a semialgebraic set into connected components


Is there any built-in function for doing decomposition of a semialgebraic set into connected components? The only way I now can think of is to use


CylindricalAlgebraicDecomposition


and to build connected componnets from its output: all terms connected with disjunction on first level are treated as vertexes of graph, two vartexes are connected if Length[FindInstance[v1 && v2, {vars}]] != 0. On produced graph usual depth-first search based algorithm is used. But intuition says that such things are usually already implemented, hence the question.



Answer



EDIT: CylindricalDecomposition has been improved since I wrote this answer, probably in v11.2! Now it takes an optional topological operation argument. As a result, one can achieve the results described as connected below simply by adding such an argument to CylindricalDecomposition:


  decomp = List @@ BooleanMinimize@CylindricalDecomposition[eqns, {x, y},
"Components"];



The code below is a bit of a cheat: it modifies sets acquired through cylindrical decomposition by converting < to <= and > to >=. This prevents some infinitesimally small gaps from being recognised as such, but wins the possibility of finding overlaps between cylindrical cells produced by CAD. It may still serve as a starting point for more "real-world" solutions.


This code constructs a pairwise graph from those DNF components of the decomposition for which their closed region overlaps with another. From this connected graph components are computed, and this gives more or less directly connected components you seek:



Module[{eqns, decomp, connected, regdim},
eqns = x^2 + y^2 <= 1 && x^2 + (y - 1/2)^2 >= 1/2 &&
! (0 <= y - x/2 <= 1/4) && ! (0 <= y/2 + x <= 1/4) &&
x^2 + (y + 3/4)^2 >= 1/32;

regdim =
RegionDimension@ImplicitRegion[Reduce[#, {x, y}, Reals], {x, y}] &;

decomp =
List @@ BooleanMinimize@CylindricalDecomposition[eqns, {x, y}];


connected =
Or @@@ ConnectedComponents@
Graph[decomp, UndirectedEdge @@@
Select[Subsets[decomp, {2}],
regdim[And @@ # //. {Less -> LessEqual, Greater -> GreaterEqual}] >= 0 &]];

(Quiet@RegionPlot[#, {x, -1, 1}, {y, -1, 1}, PlotPoints -> 100] & /@
{decomp, connected})~Join~
{FullSimplify[connected, (x | y) \[Element] Reals]}]


The result shows CAD result, "unified" connected components and each component:


enter image description here



{(Sqrt[1 - x^2] + y >= 0 && ((x > 2 y && 2/Sqrt[5] + x > 0 && Sqrt[6] + 5 x <= 1) || (Sqrt[6] + 5 x > 1 && Sqrt2 + 8 x <= 0 && Sqrt[2 - 4 x^2] + 2 y <= 1) || (x < 1/Sqrt[5] && 2 x + y < 0 && 8 x >= Sqrt2) || (Sqrt2 + 8 x > 0 && 8 x < Sqrt2 && 6 + Sqrt[2 - 64 x^2] + 8 y <= 0))) || (Sqrt[2 - 64 x^2] <= 6 + 8 y && ((8 x < Sqrt2 && 2 x + y < 0 && 10 x >= 1) || (Sqrt2 + 8 x > 0 && 10 x < 1 && Sqrt[2 - 4 x^2] + 2 y <= 1))), (1 + x == 0 && y == 0) || (Sqrt[7] + 4 x == 0 && 4 y == 3) || (Sqrt[1 - x^2] >= y && ((1 + 2 Sqrt[19] + 10 x == 0 && Sqrt[1 - x^2] + y > 0) || (Sqrt[1 - x^2] + y >= 0 && 1 + x > 0 && 1 + 2 Sqrt[19] + 10 x < 0) || (1/Sqrt2 + x > 0 && Sqrt[7] + 4 x < 0 && 1 + Sqrt[2 - 4 x^2] <= 2 y) || (1 + 2 Sqrt[19] + 10 x > 0 && 1 + 2 x < 4 y && 1/Sqrt2 + x <= 0))) || (1/Sqrt2 + x > 0 && 1 + 2 x < 4 y && Sqrt[2 - 4 x^2] + 2 y <= 1), (x == 1 && y == 0) || (Sqrt[1 - x^2] + y >= 0 && ((Sqrt[1 - x^2] >= y && x > 2/Sqrt[5] && x < 1) || (10 x > 2 + Sqrt[19] && 5 x < 1 + Sqrt[6] && Sqrt[2 - 4 x^2] + 2 y <= 1) || (x > 2 y && 5 x >= 1 + Sqrt[6] && x <= 2/Sqrt[5]))) || (10 x <= 2 + Sqrt[19] && 4 x + 2 y > 1 && Sqrt[2 - 4 x^2] + 2 y <= 1), (4 x == Sqrt[7] && 4 y == 3) || (4 x > Sqrt[7] && 10 x < 7 && 1 + Sqrt[2 - 4 x^2] <= 2 y && y <= Sqrt[1 - x^2]) || (1 + 2 x < 4 y && Sqrt[1 - x^2] >= y && 10 x >= 7)}



EDIT:


Here's an improvement to the case of infitesimal gaps. Instead of just rewriting CAD cells to closures, we search for intersection of one cell with RegionBoundary of another. RegionPlot visualisation is not particularly pretty in this case (there's a single point connecting upper and lower left side now), but that's not a problem caused by the connected components code. This version has a drawback of being considerably slower than the original answer.


Module[{eqns, decomp, connected, regconn},
eqns = x^2 + y^2 <= 1 && x^2 + (y - 1/2)^2 >= 1/2 &&

! (0 == y - x/2 && x != -3/4) && ! (0 == y/2 + x) &&
x^2 + (y + 3/4)^2 >= 1/32;

regconn =
Resolve@Exists[{x, y}, (x | y) \[Element] Reals,
RegionMember[
RegionIntersection[ImplicitRegion[#1, {x, y}],
RegionBoundary@ImplicitRegion[#2, {x, y}]], {x, y}]] &;

decomp =

List @@ BooleanMinimize@CylindricalDecomposition[eqns, {x, y}];

connected =
Or @@@ ConnectedComponents@
Graph[decomp, UndirectedEdge @@@
Select[Subsets[decomp, {2}],
regconn @@ # || regconn @@ Reverse@# &]];

(Quiet@RegionPlot[#, {x, -1, 1}, {y, -1, 1},
PlotPoints -> 100] & /@ {decomp, connected})~Join~

{FullSimplify[connected, (x | y) \[Element] Reals]}]

enter image description here



...



Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....