plotting - How do I plot a histogram with hatched shading?

I can plot an ordinary histogram with blue shading and black borders like this:

T = RandomVariate[NormalDistribution[0, 1], 10000];
Histogram[T, 30]

And I can simulate hatching like this:

T = RandomVariate[NormalDistribution[0, 1], 10000];
Histogram[T, 30, ChartElements -> Graphics[{Black, Line[{{0, 0}, {1, 1}}]}]]

How can I get the hatching and the black borders at the same time?

Answer

I was sure Histogram can be modified to have the hatching style. Little late but what about this!

g[{{xmin_, xmax_}, {ymin_, ymax_}}, ___] := Module[{yval, line},
  yval = Range[ymin, ymax, 15];
  line = Line /@ Transpose@{Most@({xmin, #} & /@ yval),Rest@({xmax, #} & /@ yval)};
  {FaceForm[White],Polygon[{{xmin, ymin}, {xmax, ymin}, {xmax, ymax}, {xmin, ymax}}],
   Orange, line}];
T = RandomVariate[NormalDistribution[0, 1], 10000];
Histogram[T, 30, ChartElementFunction -> g,
ChartBaseStyle -> EdgeForm[{Thin, Darker@Orange}], Frame -> True]

enter image description here

Check in the function where yval is defined with Range[ymin, ymax, 15] one can change the $15$ to change the amount of hatching. You also have total control of the Graphics primitive used in the ChartElementFunction so you can use many more Directive for example Opacity and all.

Comments

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plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

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