front end - Magnification, ScreenResolution, ScreenInformation and Printing: Please shine some Light into it!

According to How to set default magnification for all windows Mathematica assumes 72 dpi screen resolution. In my computer, the screen resolution actually is 120 dpi which is a very common value on recent laptops.

Since I worry about

different appearance on the screen and on printed notebooks,

characters on the screen being too small,

strange things happening when editing, sometimes the cursor operates one character left of where it is displayed, which really makes headache!

using paragraphs with a negative indent and wanting to use a tab to outdent the first word of such a paragraph

I got the idea, to set the screen resolution to 120 dpi which is very close to what my screen really has (it has 120.4 dpi, but I can't enter a decimal number here). I used OptionInspector this way:

. The original value in this place was 72. Probably It might haven been the same as executing

SetOptions[$FrontEnd, 
           FontProperties->{"AutoSpaceWidth"->{0.221`,0.439`},
                            "FontMonospaced"->Automatic,
                            "FontSerifed"->Automatic,

                            "ScreenResolution"->120
                           }
          ]

(unfortunately I find nothing in the documentation what AutoSpaceWidth influences! Does anyone have an idea, what it affects? BTW: How would I just modify the setting for ScreenResolution without affecting any of the others?).

Then I modified Default.nb to use Courier 10 pt for Input (bold), Output (regular) and Print (regular) and also I set all Text cells to Arial 10 pt. Now everything looks nice on the screen. But when I printed my notebook, everything came out as something like 6 points size, which also makes headache! (I printed in the working environment).

Later I came across a discussion about ScreenInformation

Strangely the Magnification indicated in the lower right corner and the one returned from the command differ!

Is there someone who can shine some light

which of those many adjustment screws serves which purpose and

how to set them to get WYSIWYG for Input, Output, Print and Text cells?

Comments

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

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