Skip to main content

VertexSize doesn't scale with Graph layout?


I wonder about how I could make a Graph scale automatically when I vary the size of the vertices.


I would like to visualize information with a Graph. The vertices all have e.g. additional info like a weight which I would like to visualize with the vertices drawn with different sizes.


However, when I define the sizes, the graph keeps the original (as opposed to the new) layout. The graph then becomes invisible.



Graph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4}]

shows:


Standard Graph


Now I add the "weight"


Graph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4},VertexSize -> {1 -> 1.1, 2 -> 1.2, 3 -> 1.3, 4 -> 1.4}]

This shows:


not scaled


What I would like is that the Graph would be like



nice


Any thoughts?


This is a graph currently working on. As you can see one vertex hits his neighbour. I would expect MM to or reposition this vertex a bit further or to scale down all nodes. Of course this can be done by dividing the vertexes by a number. But this is manual work to see what looks best. I hope there is another way.


other example



Answer



Does the following do what you want?


WeightedGraph[edges_, weights_, options___]:=
Block[{maxweight=Max[#[[2]]&/@weights]},
Graph[edges,VertexSize->((#[[1]]->0.9*#[[2]]/maxweight)&/@weights),options]]


WeightedGraph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,
3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4},
(*weights:*) {1 -> 1.1, 2 -> 1.2, 3 -> 1.3, 4 -> 1.4}]

Mathematica graphics


The second line is basically your Graph call, except that it uses WeightedGraph instead of Graph, and the weights don't have VertexSize-> in front of them.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.