Skip to main content

VertexSize doesn't scale with Graph layout?


I wonder about how I could make a Graph scale automatically when I vary the size of the vertices.


I would like to visualize information with a Graph. The vertices all have e.g. additional info like a weight which I would like to visualize with the vertices drawn with different sizes.


However, when I define the sizes, the graph keeps the original (as opposed to the new) layout. The graph then becomes invisible.



Graph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4}]

shows:


Standard Graph


Now I add the "weight"


Graph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4},VertexSize -> {1 -> 1.1, 2 -> 1.2, 3 -> 1.3, 4 -> 1.4}]

This shows:


not scaled


What I would like is that the Graph would be like



nice


Any thoughts?


This is a graph currently working on. As you can see one vertex hits his neighbour. I would expect MM to or reposition this vertex a bit further or to scale down all nodes. Of course this can be done by dividing the vertexes by a number. But this is manual work to see what looks best. I hope there is another way.


other example



Answer



Does the following do what you want?


WeightedGraph[edges_, weights_, options___]:=
Block[{maxweight=Max[#[[2]]&/@weights]},
Graph[edges,VertexSize->((#[[1]]->0.9*#[[2]]/maxweight)&/@weights),options]]


WeightedGraph[{1 \[UndirectedEdge] 2, 2 \[UndirectedEdge] 3,
3 \[UndirectedEdge] 1, 3 \[UndirectedEdge] 4},
(*weights:*) {1 -> 1.1, 2 -> 1.2, 3 -> 1.3, 4 -> 1.4}]

Mathematica graphics


The second line is basically your Graph call, except that it uses WeightedGraph instead of Graph, and the weights don't have VertexSize-> in front of them.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...