Skip to main content

Thread Part ([[]]) over two lists


When I try to Thread Part function over two nested arrays, the operation is performed as expected but i get a warning. I'm not sure if (and what) am I doing wrong. The code example is below.



lst1 = {{5, -9, 15}, {12, -15, 4}}
indices={{2,1,3},{1,3,2}}
Thread[Part[lst1,indices]]

and the output is


{{-9, 5, 15}, {12, 4, -15}}

as expected. However, the following warning was thrown.


Part::pkspec1: The expression {{2,1,3},{1,3,2}} cannot be used as a part specification. >>


Shouldn't Part be threaded over the list as described in the help under Thread function?



Answer



RunnyKine already explained in detail the source of the message. I would like to offer a couple of alternative formulations of a solution and comment on your attempt to use Hold.


You commented:



I tried Thread[Hold[Part[lst1,indices]]]//ReleaseHold. Apparently placed Hold at wrong place.



Indeed, for two reasons.





  1. In this expression Hold is the active head of the argument of Thread so, if it were possible, it is the head that would be distributed:


    Thread[Hold[{1, 2, 3}]]


    {Hold[1], Hold[2], Hold[3]}



  2. For Thread to operate it must see explicit arguments at second level of the expression. Hold here prevents lst1 and indices from evaluating to their full forms therefore even if (1) is solved a problem remains. To illustrate this we can use Unevaluated which is like a temporary Hold that prevents evaluation but is transparent to the function in which it appears, i.e. Thread:


    Thread[Unevaluated[Part[lst1, indices]]]  (* Part::pkspec1 printed *)



RunnyKine's use of Inactive and andre's use of Hold[Part] each get around both these problems because:




  1. They do not introduce an additional level in the expression; Hold[Part] is a compound head.


    TreeForm /@ {Hold[head[1, 2]], Hold[head][1, 2]}

    enter image description here





  2. While Part is rendered inactive the arguments of the compound head still evaluate in the default manner therefore lst1 and indices are expanded.




Another way to temporarily inactivate Part is Block:


Block[{Part}, Thread @ lst1[[indices]] ]

But as already demonstrated by ciao (rasher) this kind of inhibition is not needed as MapThread allows exactly the evaluation you want: expansion of lst1 and indices before Part is applied and evaluated.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.