Skip to main content

graphics - How to fill outside instead of inside graphical shapes?


I want to omit parts of Graphics from scenes by defining a geometric shape where details are visible, a "keyhole" of sorts, and fill all the rest as one would do to insides of the regular graphics primitives. How to accomplish this?


My best effort example this far is below, and there are several issues with it.


ClearAll[showWithHole];

showWithHole[g_Graphics, face_, edge_, shape_Graphics] :=
With[{invreg =
RegionDifference[FullRegion[2], DiscretizeGraphics[shape]],
opts = AbsoluteOptions[g]},
Show[g, Graphics[

{FaceForm[face], EdgeForm[],
MeshPrimitives[
DiscretizeRegion[invreg, 1.1 PlotRange /. opts,
MeshQualityGoal -> "Minimal"], 2],
edge,
MeshPrimitives[
BoundaryDiscretizeRegion[invreg, 1.1 PlotRange /. opts], 1]}],
Sequence @@ opts]]

EDIT:



Some improvements (particularly, hairlines are now gone!):


ClearAll[showWithHole];

showWithHole[g_Graphics, face_, edge_, shape_Graphics] :=
With[{invreg =
RegionDifference[FullRegion[2], DiscretizeGraphics[shape]],
opts = AbsoluteOptions[g]},
Show[g, Graphics[
{FaceForm[face], EdgeForm[edge],
FilledCurve[

BoundaryDiscretizeRegion[invreg,
CoordinateBounds[Transpose[PlotRange /. opts],
Scaled[0.05]]]["BoundaryPolygons"] /.
Polygon[pts_] :> {Line[pts]}]}], Sequence @@ opts]]

showWithHole[
Graphics[{Blue, Disk[{1, 0}, 3/2]}],
Directive[Opacity[1/2], White], Red,
Graphics[{Disk[{0, 0}, 1],
FilledCurve[{{Line@CirclePoints[{2, 1}, 1/2, 6]},

{Line@CirclePoints[{2, 1}, 1/4, 6]}}]}]]

enter image description here


EDIT 2:


[This is now split into an answer below.]


Answers with less kludgy approach (especially avoiding geometric region discretization step!) are still welcome.



Answer



This answer is split from evolution of the question. In its core, it relies on BoundaryDiscretizeGraphics to create polygons defining holes (note, these may be inside each other), and properties of FilledCurve with polygons inside each other to perform the intended "filling of the outside." Parts of data given to FilledCurve intentionally extend outside PlotRange, in order not to frame the plot with EdgeForm.


ClearAll[showWithHole];


showWithHole[g_Graphics, face_, edge_, shape_Graphics,
discoptions : OptionsPattern[BoundaryDiscretizeGraphics]] :=
Module[{opts, scaledbounds},
opts = AbsoluteOptions[g];
scaledbounds =
CoordinateBounds[Transpose[PlotRange /. opts], Scaled[0.1]];
Show[g, Graphics[
{FaceForm[face], EdgeForm[edge],
FilledCurve[
Prepend[BoundaryDiscretizeGraphics[shape,

PlotRange -> scaledbounds, discoptions][
"BoundaryPolygons"] /.
Polygon[pts_] :> {Line[pts]}, {Line[
Tuples[scaledbounds][[{1, 2, 4, 3}]]]}]]}],
Sequence @@ opts]]

showWithHole[
Graphics[{Red, Disk[{1, 0}, 3/2]}],
Directive[Opacity[9/10], White], Black,
Graphics[{Disk[{0, 0}, 1],

FilledCurve[{{Line@CirclePoints[{2, 1}, 1/2, 6]},
{Line@CirclePoints[{2, 1}, 1/4, 6]}}]}],
MaxCellMeasure -> 0.001]

enter image description here


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...