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matrix - Proof of the Dirac-gamma matrices identity


Given the matrices


γk=[Oiσk+iσkO]



where σk is the kth Pauli matrix


γ4=[I200I2]


γ5=γ1.γ2.γ3.γ4


The anticommutator rule is defined by [x,y]=xy+yx


Show that the anticommutator relation γu.γv+γv.γu=2δuvI is satisfied for all u,v=1,2,3,4 where I is the 4×4 identity matrix.


What I have defined is


\[ScriptCapitalO] = {{0, 0}, {0, 0}};
Subscript[\[Gamma], 1] = {{\[ScriptCapitalO], -I PauliMatrix[1]},
{I PauliMatrix[1], \[ScriptCapitalO]}};


Subscript[\[Gamma], 2] = {{\[ScriptCapitalO], -I PauliMatrix[2]},
{I PauliMatrix[2], \[ScriptCapitalO]}};

Subscript[\[Gamma], 3] = {{\[ScriptCapitalO], -I PauliMatrix[3]},
{I PauliMatrix[3], \[ScriptCapitalO]}};

Subscript[\[Gamma], 4] = {{IdentityMatrix[2], \[ScriptCapitalO]},
{\[ScriptCapitalO], -IdentityMatrix[2]}};

Subscript[\[Gamma], 5] =

Subscript[\[Gamma], 1].Subscript[\[Gamma], 2].Subscript[\[Gamma],3].Subscript[\[Gamma], 4];

One way to do this would be to show the identity holds individually. But this would be tedious. Can someone help me with a more efficient and general way to this?



Answer



Define DiracMatrix:


DiracMatrix[k_] /; k == 1 || k == 2 || k == 3 := 
ArrayFlatten[{{0, - I PauliMatrix[k]}, {I PauliMatrix[k], 0}}]

DiracMatrix[4] := ArrayFlatten[{{ IdentityMatrix[2], 0}, {0, -IdentityMatrix[2]}}]


DiracMatrix[5] := Dot @@ Table[DiracMatrix[k], {k, 4}]

To prove the identity we could check e.g.


And @@ Flatten @ 
Table[ DiracMatrix[i].DiracMatrix[k] + DiracMatrix[k].DiracMatrix[i]
== 2 KroneckerDelta[i, k] IdentityMatrix[4], {i, 4}, {k, 4}]


True


sometimes one would prefer a visual test, something like e.g.


L[i_, k_] := DiracMatrix[i].DiracMatrix[k] + DiracMatrix[k].DiracMatrix[i] -
2 KroneckerDelta[i, k] IdentityMatrix[4]
Table[ L[i, k] // MatrixForm, {i, 4}, {k, 4}] // MatrixForm

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