graphics - How can we show the boundary of a WordCloud shape?

WordCloud can arrange the words inside a shape.

data = EntityValue[CountryData[], {"Name", "Population"}];
WordCloud[data, Disk[], WordOrientation -> "Random", Frame -> True]

Mathematica graphics

As you can see from the plot range, the coordinates in the final word cloud don't seem to be related to the coordinates in the original shape specification. This is true regardless of whether the shape is specified as an image, graphics or region.

I would like to show the word cloud together the original shape. E.g. something like this (manually positioned):

I need to do this not for a disk/circle but any complex arbitrary shape. How can I achieve this? Is there any way to retrieve the mapping between the coordinates of the original shape and resulting word cloud?

Here's a random complex shape to test on: CountryData["Ethiopia", "Shape"].

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Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

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