Skip to main content

image processing - Improve TextRecognize[] on numbers


I have an image contain only numbers, and TextRecognize fail to recognize some numbers:


img=enter image description here;


TextRecognize[img]
(*826718*)

The documentation says that "The quality of recognized text may improve by enlarging the image", but no luck on this example


TextRecognize[ImageResize[img, Scaled[2]]]

(*826718*)

also tried different language, also no help


TextRecognize[ImageResize[img, Scaled[2]], Language -> "French"]
(*826718*)

I also tried Walfram|Alpha, it also gave the same results as Mathematica:


enter image description here


Are there some ways to solve the problem?



Answer




TextRecognize seems to be a work in progress, consider the following


Rasterize[Graphics[Text[Style["3", 100]]]] // TextRecognize
Rasterize[Graphics[Text[Style["a", 100]]]] // TextRecognize
Rasterize[Graphics[Text[Style["123", 100]]]] // TextRecognize
Rasterize[Graphics[Text[Style["1234", 100]]]] // TextRecognize
Rasterize[Graphics[Text[Style["hello", 100]]]] // TextRecognize
Rasterize[Graphics[Text[Style["hello 3", 100]]]] // TextRecognize

yields the following output


{nothing here}

{nothing here}
{nothing here}
1234
hello
hello 3

For reasons that are entirely unclear, single characters are not recognized as text, nor are numbers small "arrays" of numbers. Oddly enough, small numbers are recognized if preceeded with an actual word, making the following a terrible solution that nonetheless gives you the answer:


n = Import["http://i.stack.imgur.com/cPRrY.png"];
pretext = Rasterize["hello ", RasterSize -> 175, ImageSize -> 40];
Row[{pretext, ImageResize[n, 1000]}] // Rasterize;

t = TextRecognize@ImageResize[%, Scaled[5]];
StringSplit@t

gives the output


{hello,3482671897}

Let's hope someone comes up with a better answer...


Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...