Skip to main content

plotting - Aligning plot axes in a graphics object


I need to align the y-axes in the plots below. I think I'm going to have to do some rasterizing and searching for vertical lines, then vary x and w. Is there a better way?



a = ListPlot[{{0, 0}, {16, 20}},
   PlotRange -> {{0, 16}, {0, 20}}, Frame -> True];
b = ListPlot[{{0, 0}, {160000, 200000}}, 
   PlotRange -> {{0, 160000}, {0, 200000}}, Frame -> True];
x = 3.1; w = 5;
Graphics[{LightYellow, Rectangle[{0, 0}, {7, 8}], 
  Inset[a, {x, 5.5}, Center, {w, Automatic}], 
  Inset[b, {3.1, 2.2}, Center, {5, Automatic}]}, 
 PlotRange -> {{0, 7}, {0, 8}}, ImageSize -> 300]


enter image description here



Answer



This is a common (and very big) annoyance when creating graphics with subfigures. The most general (but somewhat tedious) solution is setting an explicit ImagePadding:


GraphicsColumn[
 {Show[a, ImagePadding -> {{40, 10}, {Automatic, Automatic}}], 
  Show[b, ImagePadding -> {{40, 10}, {Automatic, Automatic}}]}]

Mathematica graphics


This is tedious because you need to come up with values manually. There are hacks to retrieve the ImagePadding that is used by the Automatic setting. I asked a question about this before. Using Heike's solution from there, we can try to automate the process:


padding[g_Graphics] := 

 With[{im = Image[Show[g, LabelStyle -> White, Background -> White]]},
   BorderDimensions[im]]

ip = 1 + Max /@ Transpose[{First@padding[a], First@padding[b]}]

GraphicsColumn[
 Show[#, ImagePadding -> {ip, {Automatic, Automatic}}] & /@ {a, b}]

The padding detection that's based on rasterizing might be off by a pixel, so I added 1 for safety.


Warning: the automatic padding depends on the image size! The tick marks or labels might "hang out" a bit. You might need to use padding@Show[a, ImageSize -> 100] to get something that'll work for smaller sizes too.



I have used this method myself several times, and while it's a bit tedious at times, it works well (much better than figuring out the image padding manually).


Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more