Skip to main content

graphics - Movable text on a curve


Having an arbitrary curve defined as InterpolatingFunction, what is the best way to place a text on this curve? The text generally has two rows, for example: "This is\na text on a curve", the curve must go between the rows. I am interested both in character-based (preserving characters as selectable textual elements) and outlined solution (the text is first converted to outlines, then a transformation is applied to the resulting curves). It would be perfect to have a possibility to move the text along the curve interactively.


External links (updated!):




  1. Warping Text to a Bézier curves (Jay's Projects)





  2. Geometric shaping of a text (Wolfram Community)






For the search engine: this is also known as "text on a path."



Answer



Here's another way...Text[] has a direction argument, so ArcTan is not necessary.


txt1 = "Now we can follow" // Characters;
txt2 = "an arbitrary path" // Characters;
f[t_] := {Cos[2 π t], Sin[6 π t]};

totalarclength = NIntegrate[Sqrt[f'[τ].f'[τ]], {τ, 0, 1}];
invarclength = First@NDSolve[{D[$t[s], s] == 1/Sqrt[f'[$t[s]].f'[$t[s]]], $t[0] == 0},
$t, {s, 0, totalarclength}];
ds = 0.12;
fs = Scaled[0.08];

Manipulate[
Show[
ParametricPlot[f[t], {t, 0, 1}],
Graphics[{

Table[Text[Style[txt1[[n]], "Text", FontSize -> fs],
f[$t[Mod[s0 + n ds, totalarclength]] /. invarclength],
{0, -1.1},
f'[$t[Mod[s0 + n ds, totalarclength]] /. invarclength]],
{n, Length[txt1]}],
Table[Text[Style[txt2[[n]], "Text", FontSize -> fs],
f[$t[Mod[s0 + n ds, totalarclength]] /. invarclength],
{0, 1.1},
f'[$t[Mod[s0 + n ds, totalarclength]] /. invarclength]],
{n, Length[txt2]}]}],

PlotRangePadding -> Scaled[0.09]
],
{s0, 0, totalarclength}
]

Computing the arclength can help space the characters out. As far as I know, Mathematica does not provide access to character widths, so that equal spacing is probably as good as one can do easily. As someone has remarked, tight curvatures pose a problem.


Mathematica graphics


Addendum


One of Alexey Popkov's comments suggested the following modification, with help from the FilledCurve doc page. The glyphs are distorted by the curvature, and tight curvatures cause inversion.


txtbase = ImportString[ExportString["some movable text", "PDF"], "PDF"];

txt = First@First@txtbase;
xRange = -Subtract @@ First[PlotRange /. First@AbsoluteOptions[txtbase, PlotRange]];
c[t_] := {Cos[2 π t], Sin[6 π t]};
totalarclength = NIntegrate[Sqrt[c'[τ].c'[τ]], {τ, 0, 1}];
invarclength = First@NDSolve[{D[$t[s], s] == 1/Sqrt[c'[$t[s]].c'[$t[s]]], $t[0] == 0},
$t, {s, 0, totalarclength}];
NN[t_] := {{0, -1}, {1, 0}}.c'[t]/Sqrt[c'[t].c'[t]];
maptext[s_, Δn_] := With[{t = $t[Mod[s, totalarclength]] /. invarclength},
c[t] + Δn NN[t]];
Manipulate[

Show[
ParametricPlot[c[t], {t, 0, 1}],
Graphics[
Dynamic@{txt /. {x_Real, y_Real} :> maptext[-fs x/xRange + s0, -fs y/xRange + ΔN]}],
PlotRange -> 1.5
],
{{ΔN, 0.1}, -1, 1},
{{s0, 6.45}, 0, totalarclength},
{{fs, 2, "font scale"}, 0.1, 5}
]


Mathematica graphics


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....