Skip to main content

plotting - Strange filling


Bug introduced in 9.0 and fixed in 10.0




I observed some strange behaviour when plotting a function with filling.


The code is as follows:



fx[x_] := 1/(Exp[-x - 7] + 1) + 1/(Exp[x - 7] + 1) - 3/2

blue = RGBColor[17.6/100, 41.6/100, 63.1/100];
yellow = RGBColor[96.9/100, 68.6/100, 20.8/100];

u10 = Plot[fx[x], {x, -15, 15}, PlotRange -> All, AxesLabel -> {"x", "fx(x)"}, PlotStyle -> Directive[Dashed, AbsoluteThickness[0.5], blue], Filling -> {1 -> {Axis, {Directive[Opacity[0.75], yellow], Directive[Opacity[0.5], yellow]}}}]

u11 = Show[u10, Frame -> False, Axes -> True, AxesStyle -> Directive[AbsoluteThickness[0.3], 6, FontFamily -> "Helvetica"], ImageSize -> 120, TicksStyle -> Directive[AbsoluteThickness[0.3], 5, FontFamily -> "Helvetica"]]

Export[FileNameJoin[{HomeDirectory[],"u11.pdf"}], u11]


The problem with generated image is that only leftmost filling area is properly rendered. The central and the rightmost areas go slightly beyond the borders. The mismatch is not large, around one line-width, but visible. I attach below the generated image converted from pdf to png with 1200pt resolution.


1200ptx800pt


Notice


This is not an artefact of pdf viewers: Adobe Acrobat 8 Professional, Adobe Reader X (Windows); Preview, Adobe Illustrator CS6, Adobe Acrobat 10.1.9 (Mac) consistently produce the same picture. Preview generates some more artefacts, however, it is not important in this context.


The problem seems to be specific for Mathematica 9.0.1 for Mac and Win 7 (64 bit). I can confirm that the problem does not arise for Mathematica 6.0.1 for Win XP. Other users indicate proper rendering with versions 7 and 8.


Details


The effect does not depend on the line-style (full, dotted, etc.), on the opacity, plot-type (frame vs axes, list plot vs. plot). Reducing the line-width reduces the undesired effect, however, it is not an option for me (as explained in this post).


I would appreciate any suggestions on how to fix the problem.



Answer




This bug has been fixed as of version 10.0. The current result is


enter image description here


(used Mathematica 10.2 on OS X, but other platforms also seem fine)


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.