Skip to main content

list manipulation - How can I make threading more flexible?


Threading automatically with Listable functions requires the argument expressions to have the same length (or for one of them to be atomic). For nested lists the threading will continue down through the levels, provided the lengths are the same at each level. So, for example, these all work because the Dimensions of the two lists are the same at the first $n$ levels:


Array[#&, {10, 5, 3}] + Array[#&, {10}];
Array[#&, {10, 5, 3}] + Array[#&, {10, 5}];
Array[#&, {10, 5, 3}] + Array[#&, {10, 5, 3}];

whereas this doesn't work because the outer Dimensions don't match ($10\neq 5$):


Array[#&, {10, 5, 3}] + Array[#&, {5, 3}];

(* Thread::tdlen: Objects of unequal length ... cannot be combined. *)

But there is an obvious interpretation of the above code, which is to map the addition over the outer level of the first argument, i.e. to add the second 5x3 array to each of the ten 5x3 arrays in the first argument.


A more easily visualised example is adding an offset to a list of coordinates:


coords = {{1, 2}, {3, 4}, {5, 6}, {7, 8}};
offset = {0, 10};

One way is to explicity Map the addition over the coordinate list:


result = # + offset & /@ coords
(* {{1, 12}, {3, 14}, {5, 16}, {7, 18}} *)


If the coordinate list was very long, a more efficient approach using Transpose might be preferred:


result = Transpose[Transpose[coords] + offset]
(* {{1, 12}, {3, 14}, {5, 16}, {7, 18}} *)

Neither of these is particularly readable though. It would be nice to have a "smart" threading function that would identify that the second dimension of coords (length 2) matches the first dimensions of offset (also length 2), allowing the code to be written very readably:


result = smartThread[ coords + offset ]
(* {{1, 12}, {3, 14}, {5, 16}, {7, 18}} *)

How can I write such a smartThread function, which will take an expression of the form func_[a_, b_] and match up the various dimensions in a and b to do this kind of flexible threading?




Answer



My own solution looks like this:


SetAttributes[smartThread, HoldAll];

smartThread[f_[a_?ArrayQ, b_?ArrayQ], dir : -1 | 1 : -1] := Module[{da, db, or, o, g, t},
or = Function[{x, y, d}, Select[Permutations @ Range @ Length[x],
x[[#[[;; Length[y]]]]] == y &][[d]] ~Check~ Return[$Failed, Module]];
t = #1 ~Transpose~ Ordering[#2] &;
g = If[MemberQ[Attributes[f], Listable], f, Function[Null, f[##], Listable]];
{da, db} = Dimensions /@ {a, b};

If[Length[da] >= Length[db],
t[a, o = or[da, db, dir]] ~g~ b,
a ~g~ t[b, o = or[db, da, dir]]]
~Transpose~ o]

The function works by examining the dimensions of both input lists to determine which dimensions are "shared" (ie. have the same length) by both inputs. One of the input lists (the one with the greater ArrayDepth) is transposed such that the shared dimensions are outermost. This allows the function to thread over those dimensions, after which the Transpose is reversed.


Straightforward examples


By "straightforward", I mean cases where there is no ambiguity about how to match up the dimensions of the two input lists. For Listable functions like Plus and Times the smartThread function works as you would expect:


smartThread[{{1, 2}, {3, 4}, {5, 6}} + {10, 0}]
(* {{11, 2}, {13, 4}, {15, 6}} *)


smartThread[{{1, 2}, {3, 4}, {5, 6}} * {10, 0}]
(* {{10, 0}, {30, 0}, {50, 0}} *)

Functions which are not normally Listable are replaced internally by versions which are, so you get Thread-like behaviour:


smartThread[{{1, 2}, {3, 4}, {5, 6}} ~ Max ~ {10, 0}]
(* {{10, 2}, {10, 4}, {10, 6}} *)

smartThread[{{1, 2}, {3, 4}, {5, 6}} ~ f ~ {10, 0}]
(* {{f[1, 10], f[2, 0]}, {f[3, 10], f[4, 0]}, {f[5, 10], f[6, 0]}} *)


It should work with nested lists of any depth, provided the dimensions can be matched up. Note that the output has the same shape as whichever input has the greater ArrayDepth:


smartThread[Array[#&, {5, 7, 2, 10, 3, 4}] + Array[#&, {10, 7, 3}]] // Dimensions
(* {5, 7, 2, 10, 3, 4} *)

smartThread[Array[#&, {10, 7, 3}] + Array[#&, {5, 7, 2, 10, 3, 4}]] // Dimensions
(* {5, 7, 2, 10, 3, 4} *)

Equal ArrayDepth case


If both input lists have the same ArrayDepth, the output will be the same shape as the first one:



smartThread[Array[# &, {10, 2}] + Array[# &, {2, 10}]] // Dimensions
(* {10, 2} *)

smartThread[Array[# &, {2, 10}] + Array[# &, {10, 2}]] // Dimensions
(* {2, 10} *)

Dimension matching ambiguites


There is not always a single unique way to match up the dimensions of the input lists. Consider for example smartThread[a + b] where Dimensions[a] = {2, 3, 2} and Dimensions[b] = {3, 2}. The default behaviour of smartThread is to match the dimensions innermost first, so the result would be equivalent to {a[[1]] + b, a[[2]] + b}:


smartThread[Array[0 &, {2, 3, 2}] + {{1, 2}, {3, 4}, {5, 6}}]
(* {{{1, 2}, {3, 4}, {5, 6}}, {{1, 2}, {3, 4}, {5, 6}}} *)


If it is required to match the dimensions outermost first, you can supply +1 as a second argument to smartThread:


smartThread[Array[0 &, {2, 3, 2}] + {{1, 2}, {3, 4}, {5, 6}}, 1]
(* {{{1, 1}, {3, 3}, {5, 5}}, {{2, 2}, {4, 4}, {6, 6}}} *)

More generally, setting the second argument to n causes the code to select the n'th valid permutation of the dimensions.


Note: I would personally recommend thinking twice before using smartThread in cases where there is ambiguity over how to match dimensions in the input lists. The motivation for writing it was to allow simple constructs like smartThread[coordinateList + offset], increasing readability for code where the intention is intuitively obvious. In situations where that isn't the case, it potentially makes the code less clear than using something like Map or Transpose explicitly.


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....