Skip to main content

evaluation - How to define a functional that produces at runtime a function by evaluating selected parts in its definition?


Consider the following functional as an example:



ClearAll[urlModifier];
urlModifier[url_]:=ReplaceAll[Function@Evaluate[
Inactive[URLBuild][
URLParse[url]/.{"slot"->Inactive[StringReplace][Slot[]," "->"_"]}
]
],{Inactive[x_]:>x}];

If I evaluate it using the following command:


urlModifier["https://www.somewebsite.com/path/slot"]["hello world!"]


It fails probably because the Slot[] is not aligning with the Function.


But if I do in-place evaluation of urlModifier["https://www.somewebsite.com/path/slot"] and use the result as input:


URLBuild[<|"Scheme"->"https","User"->None,"Domain"->"www.somewebsite.com","Port"->None,"Path"->{"","path",StringReplace[Slot[]," "->"_"]},"Query"->{},"Fragment"->None|>]&["hello world!"]

It works fine.


What should I do to urlModifier to make it accept the Slot[] for its Function that it creates?



Answer



Summary


The root cause of the surprising behaviour is that Function does not recognize Slot[] when it appears within an association object (as opposed to an association constructor). To fix it, we must either "unwrap" the association object returned by URLParse or use a different approach altogether.


The Problem: Association Objects vs. Association Constructors



We can demonstrate the problem with a simpler example:


f = With[{assoc = <| "a" -> #1 |>}, assoc &]
(* <|"a" -> #1|> & *)

The function definition looks okay. But it will not work:


f["hello world!"]
(* <|"a" -> #1|> *)

We can see the structural difference between an association constructor and an association object using TreeForm:


Function[<| "a" -> # |>] // TreeForm    (* constructor *)


association constructor TreeForm


Function[Evaluate[<| "a" -> # |>]] // TreeForm    (* object *)

association object TreeForm


More discussion on this distinction can be found in (148095). See the section labelled Ambiguity of Association.


Fixing the Original Definition


We can change the original definition to unwrap the association object during the initial evaluation and to recreate it upon use. We do that using Normal@URLParse[...] and Inactive[URLBuild@*Association]. The updated definition looks like this:


ClearAll[urlModifier];
urlModifier[url_]:=ReplaceAll[Function@Evaluate[

Inactive[URLBuild@*Association][
Normal@URLParse[url]/.{"slot"->Inactive[StringReplace][Slot[1]," "->"_"]}
]
],{Inactive[x_]:>x}];

... so then:


urlModifier["https://www.somewebsite.com/path/slot"]["hello world!"]

(* "https://www.somewebsite.com/path/hello_world%21" *)


Alternative Definitions


There are simpler ways to express this operation.


For example, we could define the urlModifier operator like this:


ClearAll[urlModifier]

urlModifier[url_] :=
URLBuild[URLParse[url] /. {"slot" -> StringReplace[#, " "->"_"]}] &

We could also define it explicitly as a "curried form":


ClearAll[urlModifier]


urlModifier[url_][s_] :=
URLBuild[URLParse[url] /. { "slot" -> StringReplace[s," "->"_"]}]

The Function form offers an advantage over the curried form in that, if desired, we could perform the initial URL-parsing at the moment of creation instead of every time the generated function is used:


ClearAll[urlModifier]

urlModifier[url_] :=
With[{parsedUrl = URLParse[url]}
, URLBuild[parsedUrl /. {"slot" -> StringReplace[#, " "->"_"]}] &

]

All of these definitions give the same results as the corrected original.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.