Skip to main content

evaluation - How to define a functional that produces at runtime a function by evaluating selected parts in its definition?


Consider the following functional as an example:



ClearAll[urlModifier];
urlModifier[url_]:=ReplaceAll[Function@Evaluate[
Inactive[URLBuild][
URLParse[url]/.{"slot"->Inactive[StringReplace][Slot[]," "->"_"]}
]
],{Inactive[x_]:>x}];

If I evaluate it using the following command:


urlModifier["https://www.somewebsite.com/path/slot"]["hello world!"]


It fails probably because the Slot[] is not aligning with the Function.


But if I do in-place evaluation of urlModifier["https://www.somewebsite.com/path/slot"] and use the result as input:


URLBuild[<|"Scheme"->"https","User"->None,"Domain"->"www.somewebsite.com","Port"->None,"Path"->{"","path",StringReplace[Slot[]," "->"_"]},"Query"->{},"Fragment"->None|>]&["hello world!"]

It works fine.


What should I do to urlModifier to make it accept the Slot[] for its Function that it creates?



Answer



Summary


The root cause of the surprising behaviour is that Function does not recognize Slot[] when it appears within an association object (as opposed to an association constructor). To fix it, we must either "unwrap" the association object returned by URLParse or use a different approach altogether.


The Problem: Association Objects vs. Association Constructors



We can demonstrate the problem with a simpler example:


f = With[{assoc = <| "a" -> #1 |>}, assoc &]
(* <|"a" -> #1|> & *)

The function definition looks okay. But it will not work:


f["hello world!"]
(* <|"a" -> #1|> *)

We can see the structural difference between an association constructor and an association object using TreeForm:


Function[<| "a" -> # |>] // TreeForm    (* constructor *)


association constructor TreeForm


Function[Evaluate[<| "a" -> # |>]] // TreeForm    (* object *)

association object TreeForm


More discussion on this distinction can be found in (148095). See the section labelled Ambiguity of Association.


Fixing the Original Definition


We can change the original definition to unwrap the association object during the initial evaluation and to recreate it upon use. We do that using Normal@URLParse[...] and Inactive[URLBuild@*Association]. The updated definition looks like this:


ClearAll[urlModifier];
urlModifier[url_]:=ReplaceAll[Function@Evaluate[

Inactive[URLBuild@*Association][
Normal@URLParse[url]/.{"slot"->Inactive[StringReplace][Slot[1]," "->"_"]}
]
],{Inactive[x_]:>x}];

... so then:


urlModifier["https://www.somewebsite.com/path/slot"]["hello world!"]

(* "https://www.somewebsite.com/path/hello_world%21" *)


Alternative Definitions


There are simpler ways to express this operation.


For example, we could define the urlModifier operator like this:


ClearAll[urlModifier]

urlModifier[url_] :=
URLBuild[URLParse[url] /. {"slot" -> StringReplace[#, " "->"_"]}] &

We could also define it explicitly as a "curried form":


ClearAll[urlModifier]


urlModifier[url_][s_] :=
URLBuild[URLParse[url] /. { "slot" -> StringReplace[s," "->"_"]}]

The Function form offers an advantage over the curried form in that, if desired, we could perform the initial URL-parsing at the moment of creation instead of every time the generated function is used:


ClearAll[urlModifier]

urlModifier[url_] :=
With[{parsedUrl = URLParse[url]}
, URLBuild[parsedUrl /. {"slot" -> StringReplace[#, " "->"_"]}] &

]

All of these definitions give the same results as the corrected original.


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...