Skip to main content

How do I troubleshoot when I get a Part::partd or a Part::partw error?



Mathematica has produced the following error message:



Part::partd: Part specification ... is longer than depth of object?



What is partd?


I think I may have flattened or (unflattened) arrays and am not sure how to locate the exact object?



Answer



Two of the most common error messages that users encounter when working with parts of lists are Part::partd and Part::partw (look up Message for the error message syntax). Both of these are because the user is trying to access an invalid part of the expression (the "object" referred to in the error message), but there's a subtle difference between the two:


Part::partw


This error occurs when you're trying to obtain a part of an expression at a position longer than the Length of the expression (or subexpression). For example:



exprw = {{a, b}, {c, d, e}};
exprw[[2, 3]]
(* e *)

exprw[[1, 3]]


Part::partw: "Part 3 of {a,b} does not exist"



You can see that we tried to access the third element of a two element list and this results in an error. In general, if you get a partw error, look at the size of your index and check if it makes sense to your application. If not, you've found the source of your error. If it does, then your application/model is most likely faulty and you might want to check that instead.



Part::partd


This error occurs when you're trying to index the expression at a depth deeper than the maximum depth of the expression. In general, you can index the elements of an expression at Level $n$ by using exactly $n$ indices and you can index any element in an expression of Depth $d$ with most $d-1$ indices. However, when you try to index an expression at a depth greater than its maximum depth or you try to access an element at level $n$ with more than $n$ indices (which again translates to deeper depth), you get a partd error. For example, consider:


exprd = {{a, b}, {c, d, {e}}};

The maximum depth or Depth[exprd] is 4. Now try indexing with 4 indices:


exprd[[1, 1, 1, 1]]


Part::partd: "Part specification {{a,b},{c,d,{e}}}[[1,1,1,1]] is longer than depth of object"




So if you get a partd error, check to see if you're using the right number of indices for the given expression.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...