Skip to main content

graphics3d - Möbius transformations revealed


Möbius Transformations Revealed is a short video that vividly illustrates the simplicity of Möbius transformations when viewed as rigid motions of the Riemann sphere. It was one of the winners in the 2007 Science and Engineering Visualization Challenge and the various YouTube versions have been viewed some 2,000,000 times.


In the still image below, the colored portion corresponds to a simple square in the plane. The colored portion on the sphere is the image of the square in the plane under (inverse) stereographic projection; the sphere is then rotated into the position shown and finally projected back to the plane. The colored portion on the plane is the image of the original square under a Möbius transformation.



frame from Möbius transformations revealed


How can we implement this in Mathematica? Is it possible to create a dynamic version with Manipulate that allows us to interact with the image? Can we recreate a portion of the movie? Obviously, Mathematica can't create images of the quality of the original (which was produced with POV-Ray) but how close can we get? Can we generate color or should we stick with simple graphics primitives?



Answer



This is nowhere near as remarkable as Mark McClure's answer (which I have voted for and would upvote more if I could) but I only post it in relation to coloring to illustrated correspondence.


spc[x_, y_] := {2 x, 2 y, -1 + x^2 + y^2}/(1 + x^2 + y^2)
mt[a_, b_, c_, d_][x_, y_] :=
Through[{Re, Im}[(a x + a I y + b)/(c x + c I y + d)]]
q = Flatten[
Table[{{i - 0.1, j - 0.1}, {i - 0.1, j}, {i, j}, {i, j - 0.1}}, {i,
0.1, 1, 0.1}, {j, 0.1, 1, 0.1}], 1];

col = ColorData["Rainbow"][#/100] & /@ Range[100];
Manipulate[
qm = Map[
mt[Complex @@ a, Complex @@ b, Complex @@ c, Complex @@ d] @@ # &,
q, {2}];
planm = Map[##~Join~{0} &, qm, {2}];
Graphics3D[{Opacity[0.4],
InfinitePlane[{0, 0, 0}, {{1, 0, 0}, {0, 1, 0}}], LightBlue,
Sphere[], Opacity[1],
MapThread[{#1, Polygon@#2} &, {col, Map[spc @@ # &, qm, {2}]}],

MapThread[{#1, Polygon@#2} &, {col, planm}]}, Boxed -> False,
Background -> White, FaceGrids -> All,
PlotRange -> Table[{-3, 3}, {3}]], {{a, {1, 0}}, {0.1, 0.1}, {1,
1}}, {b, {0, 0}, {1, 1}}, {c, {0, 0}, {1, 1}}, {{d, {1, 0}}, {0.1,
0.1}, {1, 1}}, ControlPlacement -> Left]

enter image description here


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]