Skip to main content

plotting - Extracting the contour lines from an image



The Image presented is created by Mathematica ListPLot. It's a list of points out of a 512x512 grid, which meets criteria. I would like to be able to identify the points that make the contour, inside and outside, of the green "ears". Then with these points identified, average over the two contours and have a line that draws the shape. I'm not sure if this can be done in Mathematica and if it can, how to implement it. Any help would be appreciated


enter image description here


Update Another option would be to use a more restrictive criterion, which gives a plot like this.


enter image description here



Is there a way to make Mathematica connect the points and/or make a list of these points?



Answer



If you can specify your criteria as an set of inequalities:


criteria = x^4 + y^4 <= 1 && x^2 + y^2 > 0.5^2;

you can simply use ImplicitRegionand RegionBoundary:


r = ImplicitRegion[criteria, {x, y}]
Region[RegionBoundary[r]]

enter image description here



Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

plotting - How to draw some 2D curves in a 3D plot?

I want to plot several 2D curves ( Sin[x] at y=0 , Cos[x] at y=1 ) in a 3D plot, what function should i use? f[x_, y_] := Piecewise[{{0, y 0}, {Sin[x], y == 0}}] g[x_, y_] := Piecewise[{{0, y 1}, {Cos[x], y == 1}}] Plot3D[{f[x, y], g[x, y]}, {x, 0, 10}, {y, 0, 10}] doesn't work. Any ideas? Answer ParametricPlot3D[{{Sin[u], 0, u}, {Cos[u], 1, u}}, {u, 0, 20}, BoxRatios -> 1, PlotRange -> {{-2, 2}, {-.5, 2}, {0, 20}}] === update - general thoughts === I've seen the comments to this question and a few other approaches to the waterfall (or wire) plot are given in this question: Plotting several functions . Also I cannot not mention one of my favorite Mathematica blogs - Archery with this post on the story of discovery of 1st pulsar and an its infamous graphics - code is given in the post: