Skip to main content

simplifying expressions - How to Simplify equations over a Ring with Mathematica?


For example, when we work over a ring, the equation x^3=0 does not imply x^2=0 or x=0, but the vice versa is true. Can we use Mathematica to Simplify equations over a ring?



Answer



If you want to solve an equation over integer rings $\mathbb{Z}_n$ you should specify them with Modulus e.g.


Column[Solve[x^3 == 0, x, Modulus -> #] & /@ Range[2, 9]]

enter image description here


Edit


Since there was no further example of any expression to simplify over a finite ring let's define e.g. a polynomial which cannot be factorized over rationals (as Mathematica does by default)


p[x_] := x^5 + 3 x^4 + 6 x^3 - 2 x^2 + 1

Factor[p[x]]
p /@ Range[5]


1 - 2 x^2 + 6 x^3 + 3 x^4 + x^5
{9, 121, 631, 2145, 5701}

however over rings $\mathbb{Z}_n$ it is evaluated automatically with Mod[ p[x], n], (it has the Listable attribute), thus


Column[ Mod[p /@ Range[2, 10], #] & /@ Range[2, 10]]



 {{{1, 1, 1, 1, 1, 1, 1, 1, 1}},
{{1, 1, 0, 1, 1, 0, 1, 1, 0}},
{{1, 3, 1, 1, 1, 3, 1, 1, 1}},
{{1, 1, 0, 1, 4, 1, 1, 0, 1}},
{{1, 1, 3, 1, 1, 3, 1, 1, 3}},
{{2, 1, 3, 3, 2, 1, 2, 2, 1}},
{{1, 7, 1, 5, 1, 3, 1, 1, 1}},
{{4, 1, 3, 4, 1, 6, 4, 1, 0}},
{{1, 1, 5, 1, 9, 1, 1, 5, 1}} }


On the other hand you can use PolynomialMod to "simplify" a polynomial over a ring $\mathbb{Z}_n$, e.g.


Column[ PolynomialMod[ p[x], #] & /@ Range[2, 6] ]


1 + x^4 + x^5
1 + x^2 + x^5
1 + 2 x^2 + 2 x^3 + 3 x^4 + x^5
1 + 3 x^2 + x^3 + 3 x^4 + x^5
1 + 4 x^2 + 3 x^4 + x^5


So to get the table Column[ Mod[p /@ Range[2, 10], #] & /@ Range[2, 10]] as above, you can Apply as well PolynomialMod on a specific level of an adequate Table, e.g.


Column[ Apply[ PolynomialMod[ p[#2], #1] &, Table[{i, j}, {i, 2, 10}, {j, 2, 10}], {2}] ] === 
Column[ Mod[ p /@ Range[2, 10], #] & /@ Range[2, 10]]


True

In case you'd like to factorize p[x] over a finite field (for n prime $\mathbb{Z}_n$ is a field) it can be done with Modulus as well, e.g.


Column[ Factor[ p[x], Modulus -> #] & /@ Prime @ Range[4]]


enter image description here


Some related details (e.g. Extension to work with polynomials and algebraic functions over rings of Rationals extended by selected algebraic numbers) you could find here.


Consider another polynomial


w[x_] := 6 - 12 x + x^2 - 2 x^3 - x^4 + 2 x^5

you can solve the equation w[x] == 0 over the field of Rationals as well (by default Mathematica solves over Complexes, and then you needn't specify the domain), e.g.


Column[ Solve[w[x] == 0, x, #] & /@ {Integers, Rationals, Reals, Complexes} ]

enter image description here



You could factorize completely this polynomial with Extension :


Factor[ w[x]]
Factor[ w[x], Extension -> {Sqrt[2], Sqrt[3], I}]

enter image description here


There is also a package AbstractAlgebra to work with adequate algebraic concepts and a related book Exploring Abstract Algebra with Mathematica.


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...