Skip to main content

plotting - Combine Plots into a single non-rasterized Graphic with no spacing



Suppose that I have two plots, pl1 and pl2:


pl1 = Plot[x, {x, 0, 1}, Frame -> True, ImageSize -> 350]
pl2 = Plot[x^2, {x, 0, 1}, Frame -> True, ImageSize -> 350]

pl1


pl2


I would like to (1) combine these plots side-by-side in a (2) non-rasterized graphic with (3) no spacing.


I get pretty close to my desired result by using Grid with Spacings -> 0:



Grid[{{pl1, pl2}}, Spacings -> 0]

grid


The above satisfies my requirements (2) and (3): the result is non-rasterized, and there is no spacing between the plots. However, the above doesn't satisfy my requirement (1), that the plots be combined into a single Graphic object. That is, if I click on either of the plots, I see that they are separate Graphic objects:


gridA


gridB


So the above approach doesn't satisfy all of my requirements. (Why do I need the plots to be combined in a single Graphic? The reason is that I want to be able to place other Graphic objects -- e.g., text, arrows, shapes, etc. -- that span the two plots.)


Another possibility is to use ImageAssemble, but unfortunately this leads to a rasterized image:


ImageAssemble[{{pl1, pl2}}]


imageassemble


A third possibility is to use GraphicsGrid with Spacings -> 0:


GraphicsGrid[{{pl1, pl2}}, Spacings -> 0]

graphicsgrid


It seems that this produces a single Graphic object ((1)) that is not rasterized ((2)), but, unfortunately, there is spacing between the plots.


Do you have any suggestions? Is there any way to remove the spacing/padding in GraphicsGrid?



Answer



You could do something like the following:


pl1=Plot[x,{x,0,1},Frame->True,ImageSize->350, 

 ImagePadding->{{Scaled[0.05],None},{Automatic,Automatic}}];
pl2=Plot[x^2,{x,0,1},Frame->True,ImageSize->350, 
 ImagePadding-> {{None,Scaled[0.05]},{Automatic,Automatic}}];

GraphicsGrid[{{pl1,pl2}},Spacings->{Scaled[-0.07],0}]

enter image description here


This removes the padding from the graphics themselves with the option ImagePadding, and a magic number of -0.07...There is likely a better way.


Comments

Post a Comment

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more