Skip to main content

Plotting Fourier spectrum versus frequency of a signal


I have looked around here, and i am sure this has been answered, but i don't understand it. The thing is, I have taken a introductory signal processing course, and we had to use Mathematica, and i had no previous experience in Mathematica, so this made a lot of things hard for me.


Now i need to understand how to visually present the spectral content of a sampled signal. So i try something simple,


sampls = Table[Sin[n*(2 \[Pi])/1000*4], {n, 0, 2000}];

where we can assume that the sampling period is 1/1000s and we have a sinus with a frequency of 4 Hz. This signal is sampled for 2 seconds, meaning we get 8 periods of the signal.


Plot of samples


Now my naive attempt is to do this (as i saw something like this in some example somewhere):


 ListLinePlot[Abs[FourierDCT[sampls]], PlotRange -> {{0, 100}, {0, 30}}]


Now i end up with this:


output from above statement


which i can't make any sense out of...


What does it mean?


My dream is to be able to plot frequency on the x-axis and amplitude on the y-axis, so that i could present the teacher with a nice narrow peak with height 1 right above 4 on such a plot.


My mathematical knowledge is rather weak, i'm sorry to say, so be gentle with me and explain as concrete as possible. This is not primarily a mathematics course.



Answer



This is how I would do this. Define frequencies and sampling rate precisely. Then use Periodogram because it takes SampleRate as an option and rescales frequency axis automatically. Read up Docs on Periodogram - see examples there.


data = Table[{t, Sin[2 Pi 697 t] + Sin[2 Pi 1209 t]}, {t, 0., 0.1, 
1/8000.}];


ListLinePlot[data, AspectRatio -> 1/4, Mesh -> All,
MeshStyle -> Directive[PointSize[Small], Red], Frame -> True]

Periodogram[data[[All, 2]], SampleRate -> 8000, Frame -> True,
GridLines -> {{697, 1209}, None},
FrameTicks -> {{All, All}, {{697, 1209}, All}},
GridLinesStyle -> Directive[Red, Dashed], AspectRatio -> 1/4]

enter image description here



Your case specifically is also very simple - sampling rate 1 - or Automatic - and frequency max at 4/1000:


sampls = Table[Sin[n*(2 \[Pi])/1000*4], {n, 0, 2000}];

Periodogram[sampls, Frame -> True, GridLines -> {{4/1000.}, None},
GridLinesStyle -> Directive[Red, Dashed],
PlotRange -> {{0, .05}, All}]

Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.