web access - Using URLExecute to login to website

One of my students is doing summer research for a local company to help analyze some of their data. Trouble is, the web interface they provide for downloading the data only allows one to download one customer's info at a time; there are over 3000 customers to analyze.

I'd like to use Mathematica (MMA) to automate this process. Step 1: use MMA to log in to their website. I've looked at many similar posts and still struggle to understand how to use Import or URLFetch or URLExecute to accomplish this.

I can't share the company's URL, though from the page source this seems to be the relevant code:



Please sign in

I tried using

URLExecute["https://THEIR_WEB_ADDRESS.com/src/index.php?page=admin", {"username" -> "fooUser", "password" -> "fooPassword"}]

but the response seems to indicate the website doesn't understand the requested page. I also tried variations of "Username" vs "username", etc., to no avail.

Can someone point me in the right direction based on the page source? I know you won't be able to test your own answer as the actual URL is not given.

Answer

This is getting a bit too long for a comment. What you want to do is possible, in principle, but web servers can be picky about how the request should look. What we can do is to try to provide as much information as possible to help Mathematica make an acceptable request. I would start with this:

req = HTTPRequest[

   "https://THEIR_WEB_ADDRESS.com/src/index.php", <|
    Method -> "POST",
    "Query" -> {"page" -> "login"},
    "Body" -> {
      "username" -> "fooUser",
      "password" -> "fooPassword",
      "action" -> "login"
      },
    "ContentType" -> "application/x-www-form-urlencoded"
    |>];


resp = URLRead[req]

The action parameter comes from the HTML for the form.

It would be interesting to know what resp["StatusCode"] returns. If it returns OK, it would also be good to check resp["Cookies"] to see if it returned a cookie. And, of course, you can also check resp["Body"] to see what they sent back.

Please let me know how it goes.

Comments

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

Blog

Search This Blog