equation solving - How to merge permutations obtained from Solve on multiple variables?

When I compute the following expression to find integer solutions of the equation (x^2 + y^2 + z^2 == 14^2)

Solve[x^2 + y^2 + z^2 == 14^2 && x > 0 && y > 0 && z > 0, {x, y, z}, Integers]

Mathematica returns

{{x -> 4, y -> 6, z -> 12}, {x -> 4, y -> 12, z -> 6}, {x -> 6, y -> 4, z -> 12}, 
 {x -> 6, y -> 12, z -> 4}, {x -> 12, y -> 4, z -> 6}, {x -> 12, y -> 6, z -> 4}}

which are permutations of the only solution: x=4, y=6, z=12.

How can I remove other "solutions" by somehow merging the permutations? For me, x, y, and z are equivalent.

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I don't want to do the following:

First[Solve[x^2 + y^2 + z^2 == 14^2 && x > 0 && y > 0 && z > 0, {x, y, z}, Integers]]

Because I will also solve:

Solve[x^2 + y^2 + z^2 == 14^3 && x > 0 && y > 0 && z > 0, {x, y, z}, Integers]

which has more than one solution.

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Edit (by belisarius)

Is there a way to specify the equivalency to Solve[] or Reduce[] so to spare the results post-processing stage?

Answer

You can use DeleteDuplicates, DeleteDuplicatesBy (Version 10) or GatherBy as follows:

ddF = DeleteDuplicates[#, Sort[Last /@ #] == Sort[Last /@ #2] &] &;
ddbF = DeleteDuplicatesBy[#,Sort[Last/@#]&]&;
fgbF = First /@ GatherBy[#, Sort[Last /@ #] &] &;

Examples:

sol1 = Solve[ x^2 + y^2 + z^2 == 14^2 && x > 0 && y > 0 && z > 0, {x, y, z}, Integers];
sol2 = Solve[x^2 + y^2 + z^2 == 14^3 && x > 0 && y > 0 && z > 0, {x, y, z}, Integers];

ddF[sol1]
(* {{x -> 4, y -> 6, z -> 12}} *)

ddF[sol2]
(* {{x -> 2, y -> 6, z -> 52}, {x -> 2, y -> 36, z -> 38}, 
    {x -> 10,  y -> 12, z -> 50}, {x -> 12, y -> 22, z -> 46},

    {x -> 12, y -> 34,  z -> 38}, {x -> 14, y -> 28, z -> 42},
    {x -> 18, y -> 22,  z -> 44}, {x -> 20, y -> 30, z -> 38}} *)

ddbF and fgbF produce the same output.