plotting - Controlling Bar Color in BarChart precisely

I'm trying to control the color of individual bars in a BarChartwhen I pass a 2 dimensional list of data to plot. What I want to accomplish is that for each pair of adjacent bars I want to use a ColorScheme overall, however, make the right bar to be slightly Darker (see the last image for an example). No color is repeated.

I've tried various combinations of {..., {None}, etc...}, however, I can't figure out how to do what I want without flattening the list.

BarChart[RandomReal[1, {5, 2}], ChartStyle -> "Pastel"]

Mathematica graphics

BarChart[RandomReal[1, {5, 2}], ChartStyle -> {"Pastel", None}]

Mathematica graphics

I thought these might work:

colorfunc = ColorData["Pastel"];
colors = colorfunc /@ Range[0, 1, 1/4];
BarChart[RandomReal[1, {5, 2}], 
 ChartStyle -> {{colors, Darker/@colors}, None}]

but it returns an error.

BarChart[RandomReal[1, {5, 2}], ChartStyle -> {Riffle[colors, Darker[#, 0.1] & /@ colors]}]

Mathematica graphics

As I said I can accomplish what I want by flattening the list but this breaks the nice bar spacing and a lot of the automated features of the plotting.

BarChart[Flatten@RandomReal[1, {5, 2}], ChartStyle -> Riffle[colors, Darker[#, 0.1] & /@ colors]]

Mathematica graphics

How can I control specific specific bars in a BarChart with multi-dimensional data?

Comments

plotting - Plot 4D data with color as 4th dimension

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plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....

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