Skip to main content

equation solving - How to substitute the following conditions into an expression?


I have an expression: $p=a\;b\; x + b^2\; y + a\;c\; z$. I want to substitute $a\;b=1$, $b^2 = 2$ and $a\;c = 4$ to obtain $p = x + 2y + 4z$.
How can I tell Mathematica to do that? I dont know how to start.



Answer



A reliable approach would use the third argument of Reduce as variables to eliminate (see Behavior of Reduce with variables as domain)


Reduce[{p == a b x + b^2 y + a c z, a b == 1, b^2 == 2, a c == 4}, {p}, {a, b, c}]



p == x + 2 y + 4 z

In the former editions of Mathematica (ver <= 4) Reduce used the third argument for eliminating another variables. It can be still used this way though it is not documented anymore, however its trace could be found in SystemOptions["ReduceOptions"].
If Reduce didn't work this way one would exploit Solve (it is still supposed to eliminate variables), e.g.:


Apply[ Equal, Solve[{p == a b x + b^2 y + a c z, a b == 1, b^2 == 2, a c == 4}, 
{p}, {a, b, c}], {2}][[1, 1]]

or Eliminate:


Eliminate[{p == a b x + b^2 y + a c z, a b == 1, b^2 == 2, a c == 4}, 
{a, b, c}] // Reverse


or even simply appropriate rules replacement (in general this approach cannot be used seamlessly though)


p == a b x + b^2 y + a c z /. {a b -> 1, b^2 -> 2, a c -> 4} // TraditionalForm

enter image description here


Edit


It would be reasonable to mention another two functions useful in similar tasks. Taking this polynomial identiclly equal to zero:


poly = p - a b x - b^2 y - a c z;

we can rewrite it in terms of another three polynomials which are also identically zeros by the assumptions:



{poly1, poly2, poly3} = {a b - 1, b^2 - 2, a c - 4};

thus we know that the resulting polynomial will be equal to zero as well:


Last @ PolynomialReduce[ poly, {poly1, poly2, poly3}, {a, b, c, p, x, y, z}] == 0


p - x - 2 y - 4 z == 0

similarily we can find a Groebner basis of polynomials { poly, poly1, poly2, poly3} eliminating unwanted variables {a, b, c}:


First @ GroebnerBasis[{ poly, poly1, poly2, poly3}, {x, y, z}, {a, b, c},

MonomialOrder -> EliminationOrder] == 0

These two methods are more useful when we want to find different representations of (polynomial) expressions in polynomial rings, thus we needn't assume that polynomials { poly, poly1, poly2, poly3} identically vanish.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...