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Filter list based on date



What I would like to do is remove entries from a list of instrument data when it is in maintenance. The maintenance data I have is a series of dates which look like this;


{{{2009, 6, 29, 10, 41, 0.}, {2009, 6, 30, 15, 26, 0.}}, {{2009, 6, 
30, 16, 52, 0.}, {2009, 7, 1, 6, 0, 0.}}, {{2009, 7, 1, 6, 0,
0.}, {2009, 7, 1, 6, 2, 0.}}}

So between 29/6/2009 10:41 and 30/6/2008 15:26 the instrument was in maintenance.


The instrument data looks like this;


{{{2010, 1, 1, 6, 15, 0.}, 0.04375}, {{2010, 1, 1, 6, 30, 0.}, 
0.04375}, {{2010, 1, 1, 6, 45, 0.},
0.04375}, {{2010, 1, 1, 7, 0, 0.},

0.04375}, {{2010, 1, 1, 7, 15, 0.}, 0.04375}}

With the first column being the date/time and the second the value.


What I would like is a quick (the instrument data is 100,000 records) way to remove rows from the instrument data when their date falls inside a maintenance period.



Answer



Starting with:


gaps = {{{2009, 6, 29, 10, 41, 0.}, {2009, 6, 30, 15, 26, 
0.}}, {{2009, 6, 30, 16, 52, 0.}, {2009, 7, 1, 6, 0,
0.}}, {{2009, 7, 1, 6, 0, 0.}, {2009, 7, 1, 6, 2, 0.}}};


data = {{{2010, 1, 1, 6, 15, 0.}, 0.04375}, {{2010, 1, 1, 6, 30, 0.},
0.04375}, {{2010, 1, 1, 6, 45, 0.},
0.04375}, {{2010, 1, 1, 7, 0, 0.},
0.04375}, {{2010, 1, 1, 7, 15, 0.},
0.04375}, {{2009, 6, 30, 7, 26, 0.}, 0.1}};

I recommend:


maint = Interval @@ Map[AbsoluteTime, gaps, {2}];

Cases[data, {date_, _} /; ! IntervalMemberQ[maint, AbsoluteTime@date]]


Or if you prefer a form with Select like wxffles shows you could write:


makeTest[gaps_] :=
With[{maint = Interval @@ Map[AbsoluteTime, gaps, {2}]},
! IntervalMemberQ[maint, AbsoluteTime @ #[[1]]] &
]

Select[data, makeTest @ gaps]

This should be more convenient to use for multiple "gaps" lists.





This is what I believe Murta wanted to write:


removeRanges[data_, gaps_] :=
Module[{absData, absGaps},
absData = AbsoluteTime /@ data[[All, 1]];
absGaps = Interval @@ Map[AbsoluteTime, gaps, {2}];
Pick[data, ! IntervalMemberQ[absGaps, #] & /@ absData]
]

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