Skip to main content

Filter list based on date



What I would like to do is remove entries from a list of instrument data when it is in maintenance. The maintenance data I have is a series of dates which look like this;


{{{2009, 6, 29, 10, 41, 0.}, {2009, 6, 30, 15, 26, 0.}}, {{2009, 6, 
30, 16, 52, 0.}, {2009, 7, 1, 6, 0, 0.}}, {{2009, 7, 1, 6, 0,
0.}, {2009, 7, 1, 6, 2, 0.}}}

So between 29/6/2009 10:41 and 30/6/2008 15:26 the instrument was in maintenance.


The instrument data looks like this;


{{{2010, 1, 1, 6, 15, 0.}, 0.04375}, {{2010, 1, 1, 6, 30, 0.}, 
0.04375}, {{2010, 1, 1, 6, 45, 0.},
0.04375}, {{2010, 1, 1, 7, 0, 0.},

0.04375}, {{2010, 1, 1, 7, 15, 0.}, 0.04375}}

With the first column being the date/time and the second the value.


What I would like is a quick (the instrument data is 100,000 records) way to remove rows from the instrument data when their date falls inside a maintenance period.



Answer



Starting with:


gaps = {{{2009, 6, 29, 10, 41, 0.}, {2009, 6, 30, 15, 26, 
0.}}, {{2009, 6, 30, 16, 52, 0.}, {2009, 7, 1, 6, 0,
0.}}, {{2009, 7, 1, 6, 0, 0.}, {2009, 7, 1, 6, 2, 0.}}};


data = {{{2010, 1, 1, 6, 15, 0.}, 0.04375}, {{2010, 1, 1, 6, 30, 0.},
0.04375}, {{2010, 1, 1, 6, 45, 0.},
0.04375}, {{2010, 1, 1, 7, 0, 0.},
0.04375}, {{2010, 1, 1, 7, 15, 0.},
0.04375}, {{2009, 6, 30, 7, 26, 0.}, 0.1}};

I recommend:


maint = Interval @@ Map[AbsoluteTime, gaps, {2}];

Cases[data, {date_, _} /; ! IntervalMemberQ[maint, AbsoluteTime@date]]


Or if you prefer a form with Select like wxffles shows you could write:


makeTest[gaps_] :=
With[{maint = Interval @@ Map[AbsoluteTime, gaps, {2}]},
! IntervalMemberQ[maint, AbsoluteTime @ #[[1]]] &
]

Select[data, makeTest @ gaps]

This should be more convenient to use for multiple "gaps" lists.





This is what I believe Murta wanted to write:


removeRanges[data_, gaps_] :=
Module[{absData, absGaps},
absData = AbsoluteTime /@ data[[All, 1]];
absGaps = Interval @@ Map[AbsoluteTime, gaps, {2}];
Pick[data, ! IntervalMemberQ[absGaps, #] & /@ absData]
]

Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...