Consider a list like below:
ttable={{0, 2.6596 - 66.137 I}, {1/9, 2.45339 - 65.3148 I}, {2/9,
1.82053 - 62.8922 I}, {1/3, 0.720006 - 58.9982 I}, {4/
9, -0.911205 - 53.8382 I}, {5/9, -3.15056 - 47.6797 I}, {2/
3, -6.08057 - 40.8346 I}, {7/9, -9.77826 - 33.6382 I}, {8/
9, -14.3047 - 26.4282 I}, {1, -19.6947 - 19.5216 I}}`
by defining "f" as interpolating function we'll have:
f = Interpolation[ttable]
now we define ff as the following integration:
ff[\[Xi]_]:=NIntegrate[(f[rr]) Cos[rr \[Xi]], {rr, 0, 1}]
the first problem is that this function can not be calculated and I have no idea why the followoing error happens:
In[87]:= ff[.1]
During evaluation of In[87]:= NIntegrate::inumr: The integrand Cos[rr \[Xi]] InterpolatingFunction[{{0.,1.}},{4,15,0,{10},{4},0,0,0,0,Automatic,{},{},False},<<1>>,{
Developer`PackedArrayForm,{0,<<10>>},{2.6596 -66.137 I,<<8>>,-19.6947-19.5216 I}},{Automatic}][rr] has evaluated to non-numerical values for all sampling points in the region with boundaries {{0,0.111111}}. >>
Out[87]= NIntegrate[f[rr] Cos[rr \[Xi]],{rr,0,1}]
The other thing should be mentioned is that I have to use ff
in integrand of another integration like below:
NIntegrate[ff[\[Xi]] * \[Xi],{\[Xi],0,3}]
I've manipulated the former equations in many ways but none of them made an accurate output for the last integration, so I would be greatly thankful if somebody out there could help me!
Answer
The most important information is that you used your function ff
inside another NIntegrate
, because this is the source of confusion. What you have to know is that NIntegrate
doesn't start right away with the numerical calculation when you call
NIntegrate[ff[ξ]*ξ, {ξ, 0, 3}]
It will try to do some analysis of your integrand and most likely, it will try to evaluate ff[ξ]
without putting in numbers. And what happens then? Right, you call the NIntegrate
of ff
without proper numerical value of ξ
:
The solution is pretty simple: Change your definition of ff
so that it only calls its NIntegrate
body when the argument is indeed numeric:
ClearAll[ff];
ff[ξ_?NumericQ] := NIntegrate[(f[rr]) Cos[rr ξ], {rr, 0, 1}]
NIntegrate[ff[ξ]*ξ, {ξ, 0, 3}]
(* 4.28747 - 124.522 I *)
Comments
Post a Comment