plotting - Hatched Filling for ListPlot

I am plotting to data curves using ListLinePlot. I like the look of Filling, but this is going to be printed, so I want something both black and white friendly, but giving more definition and separation than changing the opacity of the filling. Ideally, I would either have one hatched and the other filled solid gray, or both hatched in opposite directions or something such that they can be identified separately. This is what I have so far that I may just use if I can't find anything better:

data1 = exPDMIABSA[[1]];
data2 = exPDMIAwater[[1]];
ListLinePlot[{data1, data2},
  PlotStyle -> {Black, Directive[Dashed, Black]},
  Filling -> Axis,

  FillingStyle -> Directive[Opacity[0.7], Gray]]

enter image description here

Three related questions I've found are

RegionPlot (or FillingStyle) using hash lines?

and

Filling a polygon with a pattern of insets

and

How can I make hatching filling of plot

but none seems to address this situation. They seem to be dealing with shapes and (region)plots and not ListPlots. While it is entirely possible that they are very closely related, I'm not sure how to use any of those answers for my situation.

Thanks

Answer

This is what I've ended up doing.

data1 = exPDMIABSA[[1]];
data2 = exPDMIAwater[[1]];
Show[ListLinePlot[{data1, data2}, 
  PlotStyle -> {Directive[Dashed, Black], Black}, 
  Filling -> {2 -> Axis}, FillingStyle -> Gray], 
 RegionPlot[
  y < Interpolation[data1, InterpolationOrder -> 1][x] && y > 0, {x, 

   300, 375}, {y, 0, 17000}, Mesh -> 50, MeshFunctions -> {1000 #1 - #2 &}, 
  BoundaryStyle -> None, MeshStyle -> Thickness[.005], 
  PlotStyle -> Transparent]]

Mathematica graphics

The RegionPlot is based on this question after a suggestion in the comments to the question by Szabolcs.

Of course the same could be done for the other region in the opposite direction by switching the sign in the MeshFunctions. Also, because of the scale, the slope of the MeshFunctions was changed. The number of hatchings can be changed by changing Mesh. The default lines were a little thin for me so I thickened them with MeshStyle -> Thickness[.005].

For certain circumstances, it might be easier to define interpolation functions for each data set such as data1func = Interpolation[data1, InterpolationOrder -> 1] and just Plot that.

To me this seemed a little simpler, faster, and more general than the answer by Kuba to this question.

Comments

plotting - Plot 4D data with color as 4th dimension

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plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....

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