Skip to main content

plotting - Click in a vector plot to plot several solutions of a system of differential equations


I am aware of the Locator button and I am aware of the Equation Trekker package, but they are not what I want to use. Here is what I specifically want to know how to do, if possible. Consider the system:


x′=2x+3yy′=3x+2y


Create a vector plot.


A = {{2, 3}, {3, 2}};
F[x_, y_] = A.{x, y};
VectorPlot[F[x, y], {x, -4, 4}, {y, -4, 4}, Axes -> True,
AxesLabel -> {x, y},
VectorScale -> {0.045, 0.9, None},

VectorPoints -> 16]

enter image description here


Now my question. What I want to be able to do is use my mouse to click a point in the vector plot and as a result, the solution trajectory will be added to the vector plot. I also want to be able to do this repeatedly, click the mouse several times and then several trajectory solutions are plotted on the vector plot starting at the clicked point initial condition.


Is this possible using Mathematica?


KGULER Suggestion: OK, gave your idea Epilog -> {vp[1], Red, PointSize[Large], Point[u]} a try:


ClearAll[a, vp, x, y]
a = {{2, 3}, {3, 2}};
vp = VectorPlot[a.{x, y}, {x, -4, 4}, {y, -4, 4},
VectorScale -> {0.045, 0.9, None}, VectorPoints -> 16];

options = {PlotStyle -> Red,
Epilog -> {vp[[1]], Red, PointSize[Large], Point[u]},
AspectRatio -> 1, Axes -> True, AxesLabel -> {"x", "y"},
Frame -> True, PlotRange -> PlotRange[vp]};

Then:


Manipulate[
z = NDSolveValue[
Thread[{x'[t], y'[t], x[0], y[0]} == Join[a.{x@t, y@t}, #]], {x@
t, y@t}, {t, -2, 1}] & /@ u;

ParametricPlot[z, {t, -2, 1}, Evaluate@options], {{u, {}}, Locator,
Appearance -> None, LocatorAutoCreate -> All}, {z, {}, None},
Paneled -> False]

But I got the following image result and the warning message: "Coordinate $CellContext`u should be a pair of numbers, or a Scaled or Offset form."


enter image description here


However, I still tried the PasteSnapshot and got an image with the dots, but for some reason I can't include it in this post.


So, what have I done wrong?




Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...