Skip to main content

plotting - How to place legend labels for Histogram and ListLinePlots correctly?


I would like to place AxesLabels:



  1. For x axis at center of the Histogram and LineListPLots.

  2. For y axis rotated 90 degree anti clockwise.



I don't see any options for it?


Histogram[Table[zcb[i],{i,mcRunHJM}],AxesLabel->{Price,Relative Frequency}]

ListLinePlot[Table[zcb[i],{i,mcRunHJM}],PlotRange->{{0,mcRunHJM},{0.9,1.1}}, PlotLabel->Style["Convergence",FontSize->12],AxesLabel->{Simulation Step,Price}]

enter image description here



Answer



For the histogram:


Labeled[Histogram[

  RandomReal[NormalDistribution[0, 1], 200]], {Rotate[
   "Relative Frequency", 90 Degree], "Price"}, {Left, Bottom}]

enter image description here


Addendum


Further to Sebastian's comment to add stats:-


data = RandomReal[NormalDistribution[0, 1], 200];
Labeled[Histogram[data,
  Epilog -> Inset[Framed[Grid[{
       {"Mean =", Mean[data]},

       {"Max =", Max[data]},
       {"Min =", Min[data]}},
      Alignment -> {{Left}}], Background -> White],
    {Right, Top}, {Right, Top}],
  BaseStyle -> {FontFamily -> "Courier"}], {Rotate[
   "Relative Frequency", 90 Degree], "Price"},
 {Left, Bottom}]

enter image description here


To show two data sets, two methods:-



dataA = RandomReal[NormalDistribution[0, 1], 200];
dataB = RandomReal[NormalDistribution[0, 1], 100];

Labeled[Histogram[{dataA, dataB},
  ChartStyle -> {ColorData[3, 4], ColorData[3, 6]},
  ChartLegends -> {
    Style[StringJoin["Set A mean = ",
      ToString[Round[Mean[dataA], 10.^-6]]],
     FontFamily -> "Courier"],
    Style[StringJoin["Set B mean = ",

      ToString[Round[Mean[dataB], 10.^-6]]],
     FontFamily -> "Courier"]}],
 {Rotate["Relative Frequency", 90 Degree],
  "Price                         "}, {Left, Bottom}]

enter image description here


For more control of appearance the second method uses ShowLegend:-


(* Specify common bin division size *)
histA = Histogram[dataA, {0.5}];
histB = Histogram[dataB, {0.5}];

(* Find common plot range and axes origin *)
minmaxA = First[PlotRange /. Options[histA, PlotRange]];
minmaxB = First[PlotRange /. Options[histB, PlotRange]];
tAB = Transpose[{minmaxA, minmaxB}];
minmaxAB = {Min[First[tAB]], Max[Last[tAB]]};
aoA = First[AxesOrigin /. Options[histA, AxesOrigin]];
aoB = First[AxesOrigin /. Options[histB, AxesOrigin]];
aoAB = Min[aoA, aoB];

Quiet[Needs["PlotLegends`"]];

Labeled[
 ShowLegend[Show[
   Histogram[dataA, {0.5},
    ChartBaseStyle -> {ColorData[3, 4], Opacity[0.5]}],
   Histogram[dataB, {0.5},
    ChartBaseStyle -> {ColorData[3, 6], Opacity[0.5]}],
   PlotRange -> {minmaxAB, {All, All}},
   AxesOrigin -> {aoAB, 0}],

  {{{Graphics[{ColorData[3, 4], Opacity[0.5], Rectangle[]}], 

     Style[StringJoin["Set A mean = ",
       ToString[Round[Mean[dataA], 10.^-6]]],
      FontFamily -> "Courier"]}, {Graphics[{ColorData[3, 6], 
       Opacity[0.5], Rectangle[]}], Style[StringJoin["Set B mean = ",
       ToString[Round[Mean[dataB], 10.^-6]]],
      FontFamily -> "Courier"]}},
   LegendPosition -> {0.2, 0.6},
   LegendSize -> {1.1, 0.25},
   LegendTextSpace -> 8,
   LegendShadow -> None}],

 {Rotate["Relative Frequency", 90 Degree], "Price      "},
 {Left, Bottom}]

enter image description here


And a matching ListLinePlot:-


linedataA = RandomReal[NormalDistribution[0, 1], 20];
linedataB = Accumulate[linedataA];

ListLinePlot[{linedataA, linedataB},
 Frame -> {{True, False}, {True, False}},

 FrameLabel ->
   Map[Style[#, {FontFamily -> "Courier", 13}] &,
   {"Simulation Step", "Price"}],
 PlotLegends -> {"Set A", "Set B"}]

enter image description here


You might find this book useful: Mathematica Navigator. It shows a lot of charting techniques.


Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more