Skip to main content

Solve Laplace equation using NDSolve


I am new to Mathematica, a friend recommended this software and started using it, in fact download the trial version to know.


I recently did a program in C to calculate numerically the solution to the Laplace equation in two dimensions for a set of points as in the figure.


enter image description here


The result was very good, finding the image below.


enter image description here


This program took me about 100 lines in C, my friend told me that Mathematica could do it in a couple of lines, which seemed quite interesting. I studied a bit and found that Mathematica can solve the Laplace and Poisson equations using NDSolve command.


However, this command requires to be given to the specific boundary conditions. The boundary condition in which $\phi = 0$, it is quite easy to introduce. But on the inside border, where $\phi = 100$, I failed to get the condition. My idea is to make this problem as follows:



            uval = NDSolveValue[{D[u[x, y], x, x] + D[u[x, y], y, y] == 
0,
u[x, 0] == u[x, 100] == u[0, y] == u[100, y] == 0,
u[40, y] == u[60, y] == u[x, 40] == u[x, 60] == 100},
u, {x, 0, 100}, {y, 0, 100}]

But this does not work, and I could not give the boundary conditions on the inner square. Any help would be the most grateful.



Answer



You need a DirichletCondition (new in V10) here. Using regions (also from V10):


Ω = RegionDifference[Rectangle[{0, 0}, {100, 100}], Rectangle[{40, 40}, {60, 60}]];

sol = NDSolveValue[{
D[u[x, y], x, x] + D[u[x, y], y, y] == 0,
DirichletCondition[u[x, y] == 100.,
x == 40 && 40 <= y <= 60 ||
x == 60 && 40 <= y <= 60 ||
40 <= x <= 60 && y == 40 ||
40 <= x <= 60 && y == 60],
u[x, 0] == u[x, 100] == u[0, y] == u[100, y] == 0
}, u, {x, y} ∈ Ω]


DensityPlot[sol[x, y], {x, y} ∈ Ω, Mesh -> None, ColorFunction -> "Rainbow",
PlotRange -> All, PlotLegends->Automatic]

Mathematica graphics


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Adding a thick curve to a regionplot

Suppose we have the following simple RegionPlot: f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}] Now I'm trying to change the curve defined by $y=g[x]$ into a thick black curve, while leaving all other boundaries in the plot unchanged. I've tried adding the region $y=g[x]$ and playing with the plotstyle, which didn't work, and I've tried BoundaryStyle, which changed all the boundaries in the plot. Now I'm kinda out of ideas... Any help would be appreciated! Answer With f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 You can use Epilog to add the thick line: RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}, PlotPoints -> 50, Epilog -> (Plot[g[x], {x, 0, 2}, PlotStyle -> {Black, Thick}][[1]]), PlotStyle -> {Directive[Yellow, Opacity[0.4]], Directive[Pink, Opacity[0.4]],