Skip to main content

differential equations - Fails to apply NonlinearModelFit on a numerically evaluated model defined as a system of ODEs


I call for your help with because I'm getting troubles to fit a model defined through a system of ODEs. The system of ODEs is as follows:


X'[t]:= m[t].X[t]
X[t_] := {h[t], r[t], rh1[t], rh2[t], rh3[t]}
m[t_] := {{-k1*r[t], 0, ki1, 0, 0}, {0, -k1*h[t], ki1, 0, 0}, {0, k1*h[t], -(ki1 + k2), ki2, 0}, {0, 0, k2, -(ki2 + k3), ki3}

(It describes a chemical reaction consisting in three sequential steps, the first one is a bimolecular association and the following steps are unimolecular reactions). And the actual quantity I need to evaluate is:


F:= aF.X[t]

aF:={0,aR,aRH1,aRH2,aRH3}

(This quantity represents what I can measure experimentally). Well, following the directions found in the Wizard and in several forums I've tried the following.


Definition of the model:


Clear[modelo];
modelo[k1_?NumberQ, ki1_?NumberQ, k2_?NumberQ, ki2_?NumberQ, k3_?NumberQ, ki3_?NumberQ, aR_?NumberQ, aRH1_?NumberQ, aRH2_?NumberQ, aRH3_?NumberQ, Ht_?NumberQ, Rt_?NumberQ]:= (modelo[k1, ki1, k2, ki2, k3, ki3, aR, aRH1, aRH2, aRH3, Ht, Rt] = Module[{X, X0, m, vectorR, aF, sol, F}, First[{F, {X[t_] := {h[t], r[t], rh1[t], rh2[t], rh3[t]};
X0 := X[0] == {Ht, Rt, 0, 0, 0};
m[t_] := {{-k1*r[t], 0, ki1, 0, 0}, {0, -k1*h[t], ki1, 0,
0}, {0, k1*h[t], -(ki1 + k2), ki2, 0}, {0, 0,
k2, -(ki2 + k3), ki3}, {0, 0, 0, k3, -ki3}};

aF := {0, aR, aRH1, aRH2, aRH3};
sol :=
NDSolve[{X'[t] == m[t].X[t], X0}, {h, r, rh1, rh2, rh3}, {t,
0, 500}];
F := aF.Flatten[(X[t] /. sol)] - aR*Rt}}]])

The model so defined seems to work since, for example, it was evaluated and plotted smoothly by the following command:


aF = 0.0034;
Ht = 800;
Rt = 62; (*The last three quantities are not fitting parameters but fixed ones, whose values are known. *)

Fsim := With[{k1 = 0.0012, ki1 = 5, k2 = 0.43, ki2 = 0.0055, k3 = 0.01, ki3 = 0.0096, aRH1 = .032, aRH2 = .01, aRH3 = .012}, modelo[k1, ki1, k2, ki2, k3, ki3, aR, aRH1, aRH2, aRH3, Ht, Rt]];
LogLinearPlot[Evaluate[Fsim], {t, 0.001, 500}, PlotRange -> All, FrameLabel -> {"t(s)", "F"}]

Data and Fitting procedure:


To test that things work, I tried to fit the model to only one time series. Here is a fake data table:


data = Table[{t, .22 (1 - E^(-7.2 t)) + 0.10 (1 - E^(-0.084 t)) + 0.15 (1 - E^(-0.027 t))}, {t, 0, 500, 0.1}]

which actually proceeds from a fitting of that function to the real experimental data.


Finally, I've tried the following code to fit the model (only three parameters of it) to these data:


k1 = 0.0012;

k2 = 0.43;
ki2 = 0.0055;
k3 = 0.01;
ki3 = 0.0096;
aR = 0.0034;
Ht = 800;
Rt = 62; (*The last three quantities are not fitting parameters but fixed ones, whose values are known. *)
fit = NonlinearModelFit[data, {modelo[k1, ki1, k2, ki2, k3, ki3, aR, aRH1, aRH2, aRH3, Ht, Rt], {2 <= ki1 <= 20, 0.001 <= aRH1 <= 0.1, 0.001 <= aRH2 <= 0.1, 0.001 <= aRH3 <= 0.1}}, {{ki1, 5}, {aRH1, .032}, {aRH2, .01}, {aRH3, .012}}, t]

The problem is that it never worked, and I don't know where is the issue. It returns the following errors:




NonlinearModelFit::nrnum: The function value 1/2 ((-0.700176+<<3>>+0.0034 InterpolatingFunction[{{<<2>>}},{4,7,1,{<<1>>},{<<1>>},0,0,0,0,Automatic, },{},False},{{<<563>>}},{Developer`PackedArrayForm,{<<564>>},{<<1126>>}},{Automatic}][t])^2+(-0.700176+<<3>>+0.0034 InterpolatingFunction[{{<<2>>}},{4,7,1,{<<1>>},{<<1>>},0,0,0,0,Automatic,{},{},False},{{<<563>>}},<<1>>,{Automatic}][t])^2+(-0.700175+<<3>>+0.0034 <<1>>)^2+(<<1>>)^2+(<<1>>)^2+<<1>>^2+<<39>>+<<1>>+(<<1>>)^2+(<<1>>)^2+(<<1>>)^2+(-0.536879+<<3>>+0.0034 InterpolatingFunction[{{<<2>>}},<<3>>,{<<9>>}][t])^2+<<1>>) is not a real number at {ki1,aRH1,aRH2,aRH3} = {5.,0.032,0.01,0.012}. >>



All suggestions will be welcome.



Answer



As I find your expressions difficult to work with, let me rewrite them somewhat:


Clear[modelo];
modelo[k1_?NumberQ, ki1_?NumberQ, k2_?NumberQ, ki2_?NumberQ, k3_?NumberQ,
ki3_?NumberQ, aR_?NumberQ, aRH1_?NumberQ, aRH2_?NumberQ, aRH3_?NumberQ,
Ht_?NumberQ, Rt_?NumberQ] :=

modelo[k1, ki1, k2, ki2, k3, ki3, aR, aRH1, aRH2, aRH3, Ht, Rt] =
Module[{X, m, aF, sol},
X[t_] := {h[t], r[t], rh1[t], rh2[t], rh3[t]};
m[t_] := {{-k1*r[t], 0, ki1, 0, 0}, {0, -k1*h[t], ki1, 0, 0},
{0, k1*h[t], -(ki1 + k2), ki2, 0}, {0, 0, k2, -(ki2 + k3), ki3},
{0, 0, 0, k3, -ki3}};
aF = {0, aR, aRH1, aRH2, aRH3};
sol = NDSolve[ {X'[t] == m[t].X[t], X[0] == {Ht, Rt, 0, 0, 0}}, X[t], {t, 0, 500}];
Function[{tu}, Evaluate[aF.Flatten[X[t] /. sol] - aR*Rt] /. t :> tu]]


data = Table[{t, .22 (1 - E^(-7.2 t)) + 0.10 (1 - E^(-0.084 t)) +
0.15 (1 - E^(-0.027 t))}, {t, 0, 500, 1}];

k1 = 0.0012; k2 = 0.43; ki2 = 0.0055; k3 = 0.01; ki3 = 0.0096;
aR = 0.0034; Ht = 800; Rt = 62;
fit =
NonlinearModelFit[data,
{modelo[k1, ki1, k2, ki2, k3, ki3, aR, aRH1, aRH2, aRH3, Ht, Rt][t],
{2 <= ki1 <= 20, 0.001 <= aRH1 <= 0.1, 0.001 <= aRH2 <= 0.1, 0.001 <= aRH3 <= 0.1}},
{{ki1, 5}, {aRH1, .032}, {aRH2, .01}, {aRH3, .012}}, t,

Method -> {NMinimize, Method -> "NelderMead"}]

fit["BestFitParameters"]
(* {ki1 -> 7.23261, aRH1 -> 0.0364504, aRH2 -> 0.0108148, aRH3 -> 0.0116011} *)

Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.