Skip to main content

manipulate - Variable scoping confusion


Forgive me if this question has been asked prior (I wouldn't even know where to start looking for an answer to this problem to be honest). I know the following code in Mathematica works:


temp = {x^2,Sin[x]}; (* Just a random list with functions inside *)
f = Function[x,Evaluate[temp[[1]]]];
f[3]

The code would output the appropriate 9 as required. However, the problem occurs when I try to use a similar logic within a Manipulate function as shown below:


Manipulate[

Module[{temp,f},
temp = {x^2,Sin[x]};
f = Function[x,Evaluate[temp[[1]]]];
{num, f[num]}],
{num, 3}]

Running the above code yields an output {3, x^2} and it doesn't change for any num. Any suggestions would be exceedingly helpful. For context as to why I'm doing this, I'm solving a differential equation within the Manipulate expression (where end conditions are manipulated by the controls). Using DSolve outputs the required functions in a list and I would simply like to graph them and their derivatives. If you know a better method of doing that, that would also be helpful.


Update


It appears that the problem is, in fact, with variable typing as shown below:


temp = {x^2, Sin[x]}; (*Just a random list with functions inside*)

f = Function[x, Evaluate[temp[[1]]]];
f[3]
Manipulate[
Module[{temp, f},
temp = {x^2, Sin[x]};
f = Function[x, Evaluate[temp[[1]]]];
{Head[temp], Head[f], Head[f[num]], Head[f[3]]}],
{num, 5}]
{Head[temp], Head[f], Head[f[3]]}


Note that the Head[f[num]] and Head[f[3]] within the Manipulate expression evaluate to Power whereas the Head[f[3]] outside evaluates to Integer (as expected). Using IntegerPart[] however still doesn't yield an appropriate answer. Any thoughts?



Answer



I misdiagnosed the problem originally, somehow assuming Manipulate was the culprit, when in fact it is Module, as @Kuba pointed out (thanks!). This is discussed in this Q&A:


Enforcing correct variable bindings and avoiding renamings for conflicting variables in nested scoping constructs


I would add that renaming the argument x to x$ in Function[x, Evaluate[body]] occurs whenever the body contains Module variables other than the Function argument(s).


Module[{temp, f},
temp = {x^2, Sin[x]};
f = Function[x, Evaluate[temp[[1]]]];
f]
(* Function[x$, x^2] *)


However, no renaming occurs in the following, even though x is a Module variable: the argument stays x and perhaps unexpectedly, the instances of x in the body are not renamed to the Module variable x$746197, even though the expression is evaluated first. (This is discussed in "I define a variable as local to a module BUT then the module uses its global value! Why?")


Module[{temp, f, x},
f = Function[x, Evaluate[{x^2, Sin[x]}[[1]]]];
{x, f}]
(* {x$746197, Function[x, x^2]} *)

Original answer:


Under certain conditions, localized variables are changed when code is inserted into the localized body:


Manipulate[

Module[{temp, f},
temp = {x^2, Sin[x]};
f = Function[x, Evaluate[temp[[1]]]];
{num, f[num], f}],
{num, 3}]

Mathematica graphics


Note that the function argument has been changed to x$, which does not match the x in the body. I'm not sure why; "Manipulate is a strange beast" has been said before.


Try this:


Manipulate[

Module[{temp, f},
temp = {x^2, Sin[x]};
f = Function @@ {x, temp[[1]]};
{num, f[num], f}],
{num, 3}]

Mathematica graphics


Related:



Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...