Skip to main content

performance tuning - How can I make this program work faster?


Previous question: Can any one help me make my program work faster?


This question is an extension to the question I asked previously and referred to in the link above. I want to add spin to my system, so I changed it to the following code. the problem is that although I am using Compile, it is still very slow. I didn't change it much, so I don't understand why it is becoming so slow?


This is the code after including the spin by using the function kdfxn which acts as a delta function. gives 1 in case I have equal spin for instance if sz1 and sz2 are equal and gives 0 otherwise. The only changed I made is in chmat, the rest is the same as previous.


 nvec = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18,
19, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17,

18, 19, 20};
svec = {-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, \
-1, -1, -1, -1, -1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1};
ne = 5;
nμ = 40;
δ = -150;
β = 1;
kdfxn[i_, j_] := If[i == j, 1, 0]
avec = {{1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {0,
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {0, 0, 1, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {0, 0, 0, 1, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 1, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0}};


cfxn = Block[{n1a, n1b, n2a, n2b},
With[{code = Which[
n1a == n1b && n2a == n2b,
Evaluate[N[1/6 (1 - 3/(n1a^2 π^2) - 3/(n2a^2 π^2))]],

n1a == n1b && n2a != n2b,
Evaluate[N[(4 (1 + (-1)^(n2a + n2b)) n2a n2b)/((n2a^2 - n2b^2)^2 π^2)]],

n1a != n1b && n2a == n2b,
Evaluate[N[(4 (1 + (-1)^(n1a + n1b)) n1a n1b)/((n1a^2 - n1b^2)^2 π^2)]],


True,
Evaluate[N[-((32 (-1 + (-1)^(n1a + n1b)) (-1 + (-1)^(n2a + n2b)) n1a n1b
n2a n2b)/((n1a^2 - n1b^2)^2 (n2a^2 - n2b^2)^2 π^4))]]
]},
Compile[{{n1a, _Integer}, {n1b, _Integer}, {n2a, _Integer}, {n2b,
_Integer}},
code,
CompilationTarget -> "C"
]

]];

This is the same function as previous question, which I did not change, and it will be use later to calculate a matrix:


   chmat = With[{ccfxn = cfxn, kkdfxn = kdfxn}, 
Compile[{{nm, _Integer}, {ne, _Integer}, {b, _Real}, {d, _Real}, \
{avec, _Real, 2}, {nvec, _Real, 1}, {svec, _Real, 1}},
Block[{sz0, sz1, sz2, sz3, n0, n1, n2, n3, h1, h2, tmp, tmp2,
tmp21, kf01, kf23, kf13, kf02},
Table[n0 = Compile`GetElement[nvec, nm0];
n1 = Compile`GetElement[nvec, nm1];

sz0 = Compile`GetElement[svec, nm0];
sz1 = Compile`GetElement[svec, nm1];
tmp = 0.;
Do[sz2 = Compile`GetElement[svec, nm2];
sz3 = Compile`GetElement[svec, nm3];
n2 = Compile`GetElement[nvec, nm2];
n3 = Compile`GetElement[nvec, nm3];
tmp2 = ccfxn[n1, n0, n3, n2];
tmp21 = ccfxn[n1, n3, n0, n2];


kf01 = kkdfxn[sz0, sz1];
kf23 = kkdfxn[sz2, sz3];
kf13 = kkdfxn[sz1, sz3];
kf02 = kkdfxn[sz0, sz2];

Do[
tmp += (tmp2 kf23 kf01 - tmp21 kf13 kf02) Compile`GetElement[
avec, j, nm3] Compile`GetElement[avec, j, nm2], {j, 1,
ne}], {nm2, 1, nm}, {nm3, 1, nm}];
d tmp +

If[nm0 == nm1, (n0^2 Pi^2 + b Compile`GetElement[svec, nm0]),
0.], {nm0, 1, nm}, {nm1, 1, nm}]], CompilationTarget -> "C",
CompilationOptions -> {"InlineCompiledFunctions" -> True},
RuntimeOptions -> "Speed"]];

and then I use the iteration method to converge the energies, which is the same as previous question and the speed is fine,:


  Table[
hmat = chmat[nμ, ne, δ, β, avec, nvec, svec];
{evals, evecs} = Eigensystem[hmat];
pos = Ordering[evals][[1 ;; ne]];

bvec = Map[x \[Function] If[Total[x] < 0, -x, x], evecs[[pos]]];
residual = Max[Abs[avec - bvec]];
avec = bvec;
{residual, Total[evals[[pos]]]},
{j, 1, 30}]

I wish some one could tell me why does it become so slow as I have included spin, and is there any way I can make it work faster?



Answer



Despite telling myself I wouldn't fix this, here you are... Your problem is that you can't Compile DownValues.


Replace kdfxn with (If[# == #2, 1, 0] &) and it'll work fine.



It might help to read up on Compile a bit so this won't be an issue in the future


P.S. KroneckerDelta already exists in the language and if you were to do your own version you'd want to use === instead of ==


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...