Skip to main content

plotting - ParametricPlot3D etc. with parameters satisfying an implicit relation


I need some help on plotting the curve generated by a vector, given its three components as a function of two parameters, e.g. s1 and s2, whose range are known, and they have to satisfy a given constraint equation. Below is a simple example:


I can plot a surface of such a vector e.g. : ParametricPlot3D[{s1, s2, s1}, {s1, 0, 2 Pi}, {s2, 0, 2 Pi}], which gives a plane. Now I need to add a constraint, e.g. Cos[s1] + Cos[s2] + Cos[s1] Cos[s2] = -1. Then I expect the desired figure to be a curve. But I wonder how to plot this curve? Should I use the ParametricPlot3D function or what else? and how?


Please note that the above is just a simple example, and in my case, I may not be able solve for the constraint equation.


Thanks for any suggestions!


Update II:



Finally I notice that the answer by Michael is probably right, the inconsistence is due to my formulation error, so I have deleted that part. Thanks a lot for all the help!



Answer



One way is to use MeshFunctions to plot F[..] = 0:


MeshFunctions -> {Function[{x, y, z, s1, s2},
Cos[s1] + Cos[s2] + Cos[s1] Cos[s2] + 1]},
Mesh -> {{0}}, MeshStyle -> {Directive[Thick, Lighter@Blue]}

The function F is the mesh function


Function[{x, y, z, s1, s2}, Cos[s1] + Cos[s2] + Cos[s1] Cos[s2] + 1]


where the equation F[..] == 0 is specified by the option Mesh -> {{0}}.


Here is a look at the solution, with a more complicated surface:


GraphicsRow[{
(* the curve + surface *)
ParametricPlot3D[{s1, s2, s1^2/2 - Pi s1 + Cos[2 s2]}, {s1, 0,
2 Pi}, {s2, 0, 2 Pi},
MeshFunctions -> {Function[{x, y, z, s1, s2},
Cos[s1] + Cos[s2] + Cos[s1] Cos[s2] + 1]},
Mesh -> {{0}}, MeshStyle -> {Directive[Thick, Lighter@Blue]}],


(* the curve *)
ParametricPlot3D[{s1, s2, s1^2/2 - Pi s1 + Cos[2 s2]}, {s1, 0,
2 Pi}, {s2, 0, 2 Pi},
MeshFunctions -> {Function[{x, y, z, s1, s2},
Cos[s1] + Cos[s2] + Cos[s1] Cos[s2] + 1]},
Mesh -> {{0}}, MeshStyle -> {Directive[Thick, Lighter@Blue]},
PlotStyle -> None]
}]

Mathematica graphics



Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....