Skip to main content

bugs - Can't get Append to append a record (association) to a dataset


Bug introduced in 10.0.0 and fixed in 10.1 or earlier




The Documentation Center item, Computation with Structured Datasets, implies that Append has been extended in V10 to work with datasets. But not on my computer. (I am running on OS X)


Here is what I tried:


ds = 
Dataset[{<|"a" -> 1, "b" -> "x"|>, <|"a" -> 2, "b" -> "y"|>,

<|"a" -> 3, "b" -> "z"|>, <|"a" -> 4, "b" -> "x"|>}]

dataset


Append[ds, <|"a" -> 5, "b" -> y|>]

failure


However, insertion


Insert[ds, <|"a" -> 5, "b" -> y|>, -1]

works fine.



insert


I don't know whether I've found a bug in Appendin combination with a dataset or whether I am misreading the documentation. Are others experiencing what I am? Or can someone explain what I did wrong?


Update


I should have pointed out that I already knew that appending Append[ds, <|"a" -> 5, "b" -> "y"|>] worked. But why does it fail when given an unbound symbol? And why should Insert behave differently when given an unbound symbol? Is V10 attempting to enforce some kind of a type consistency on the values of associations? That would be very un-Mathematica like.



Answer



This is interesting:


If you replace the symbol y with the string "y", Append works fine.


Append[ds, <|"a" -> 5, "b" -> "y"|>]

Mathematica graphics



Also, if you start out with Symbols, then it works fine:


ds = Dataset[{<|"a" -> 1, "b" -> x|>, <|"a" -> 2, "b" -> y|>, <|
"a" -> 3, "b" -> z|>, <|"a" -> 4, "b" -> x|>}]

Mathematica graphics


Then:


Append[ds, <|"a" -> 5, "b" -> y|>]

Mathematica graphics


Using the Undocumented second argument we can force the Dataset on creation to expect AnyType of type:



Needs["TypeSystem`"];

dst = Dataset[{<|"a" -> 1, "b" -> "x"|>, <|"a" -> 2, "b" -> "y"|>, <|
"a" -> 3, "b" -> "z"|>, <|"a" -> 4, "b" -> "x"|>},
Vector[Struct[{"a", "b"}, {Atom[Integer], AnyType}]]]

Mathematica graphics


Now Append works even if we feed it a Symbol instead of a String:


Append[dst, <|"a" -> 5, "b" -> y|>]


Mathematica graphics


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...