Skip to main content

bugs - Can't get Append to append a record (association) to a dataset


Bug introduced in 10.0.0 and fixed in 10.1 or earlier




The Documentation Center item, Computation with Structured Datasets, implies that Append has been extended in V10 to work with datasets. But not on my computer. (I am running on OS X)


Here is what I tried:


ds = 
Dataset[{<|"a" -> 1, "b" -> "x"|>, <|"a" -> 2, "b" -> "y"|>,

<|"a" -> 3, "b" -> "z"|>, <|"a" -> 4, "b" -> "x"|>}]

dataset


Append[ds, <|"a" -> 5, "b" -> y|>]

failure


However, insertion


Insert[ds, <|"a" -> 5, "b" -> y|>, -1]

works fine.



insert


I don't know whether I've found a bug in Appendin combination with a dataset or whether I am misreading the documentation. Are others experiencing what I am? Or can someone explain what I did wrong?


Update


I should have pointed out that I already knew that appending Append[ds, <|"a" -> 5, "b" -> "y"|>] worked. But why does it fail when given an unbound symbol? And why should Insert behave differently when given an unbound symbol? Is V10 attempting to enforce some kind of a type consistency on the values of associations? That would be very un-Mathematica like.



Answer



This is interesting:


If you replace the symbol y with the string "y", Append works fine.


Append[ds, <|"a" -> 5, "b" -> "y"|>]

Mathematica graphics



Also, if you start out with Symbols, then it works fine:


ds = Dataset[{<|"a" -> 1, "b" -> x|>, <|"a" -> 2, "b" -> y|>, <|
"a" -> 3, "b" -> z|>, <|"a" -> 4, "b" -> x|>}]

Mathematica graphics


Then:


Append[ds, <|"a" -> 5, "b" -> y|>]

Mathematica graphics


Using the Undocumented second argument we can force the Dataset on creation to expect AnyType of type:



Needs["TypeSystem`"];

dst = Dataset[{<|"a" -> 1, "b" -> "x"|>, <|"a" -> 2, "b" -> "y"|>, <|
"a" -> 3, "b" -> "z"|>, <|"a" -> 4, "b" -> "x"|>},
Vector[Struct[{"a", "b"}, {Atom[Integer], AnyType}]]]

Mathematica graphics


Now Append works even if we feed it a Symbol instead of a String:


Append[dst, <|"a" -> 5, "b" -> y|>]


Mathematica graphics


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....