Skip to main content

graphics - Text[] with offset not positioned correctly in M11.1 and M11.2


Bug introduced in 11.1 and persisting through 11.3




When the first argument of Text is a Graphics, and the third argument (offset) is used, positioning is incorrect in M11.1 and M11.2. Mathematica 11.0 behaves correctly.


Example:


inset = Graphics[{Circle[{0, 0}, 2]}, Frame -> True, 
  FrameTicks -> None, ImagePadding -> 1, PlotRangePadding -> None, 
  ImageSize -> 90]

Inset


figure = Graphics[
  {Text[inset, Scaled[{0.5, 0.5}], {1, 1}]},
  PlotRange -> {{0, 1}, {0, 1}},

  Frame -> True,
  GridLines -> {Range[0, 1, .1], Range[0, 1, .1]},
  ImageSize -> 360
  ]

Incorrect positioning


(This is wrong)


With the {1,1} offset, the upper right corner of the inset should line up with the middle of the plot range in the enclosing figure.


In Mathematica 11.0 we get the expected output:


Correct positioning



In M11.1 and 11.2 we also get a correct positioning if the inset is a general notebook expression instead of a Graphics. We can, for example, wrap it in Framed to achieve this.


figure = Graphics[
  {Text[Framed[inset], Scaled[{0.5, 0.5}], {1, 1}]},
  PlotRange -> {{0, 1}, {0, 1}},
  Frame -> True,
  GridLines -> {Range[0, 1, .1], Range[0, 1, .1]},
  ImageSize -> 360
  ]

Correct positioning with Framed



Is there a workaround for this bug?



This bug is of concern to me because MaTeX-generated expressions are supposed to be a drop-in replacement for text. It is supposed to work when written directly within Text. But MaTeX outputs Graphics, so it is affected by this bug. In some situations, the user can't even control if some expression they input will be used inside of a Text or an Inset.




Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...
Post a Comment
Read more

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...
Post a Comment
Read more