Skip to main content

NDSolve mixing many scalar and vector equations


I have a set of scalar equations in many unknowns, which I want to combine with a vector equation inside an NDSolve. The equations are a mix of differential and algebraic equations.


A set of scalar equations:


eqns = {-a[0][t] + a[1][t] == 0, a[1]'[t] == - fx[1][t] + fy[1][t] - a[1][t],
a[2]'[t] == - fx[2][t] + fy[2][t] - a[2][t], a[2][t] + a[3][t] == 0,
0 == x[0][t], a[1][t] == - x[0][t] + x[2][t], a[2][t] == - x[1][t] + x[3][t],
a[3][t] == x[1][t] + x[3][t], 1 == y[0][t], a[1][t] == - y[0][t] + y[2][t],
a[2][t] == - y[1][t] + y[3][t], a[3][t] == -y[2][t] + y[3][t]};

Along with a vector equation, defined using a function fCalc.



feqn = {{fx[0][t], fy[0][t]}, {fx[1][t], fy[1][t]}, {fx[2][t], fy[2][t]}, {fx[3][t], fy[3][t]}} == 
fCalc[{{x[0][t], y[0][t]}, {x[1][t], y[1][t]}, {x[2][t], y[2][t]}, {x[3][t], y[3][t]}}];

My actual function fCalc is complicated, but it only evaluates for numerical input. It takes a list of {x,y} points and returns a list of {x,y} points, for instance:


fCalc[pts_ /; MatrixQ[pts, NumericQ]] := pts

Some initial conditions and the variables used:


initcs = {a[0][0] == 0, a[1][0] == 0, a[2][0] == 0, a[3][0] == 0};
vars=Flatten[Table[{a[j], x[j], y[j], fx[j], fy[j]}, {j, 0, 3}]];


Trying to solve this directly gives an error, as Mathematica tries to evaluate this vector function before starting, and refuses to start as it doesn't see enough equations for the unknowns.


NDSolve[{eqns, feqn, initcs},vars, {t, 0, 1}];
NDSolve::underdet: There are more dependent variables, than equations, so the system is underdetermined.

Removing the numerical requirement the system is well-defined:


fCalc2[pts_] := pts
AbsoluteTiming[NDSolve[{eqns, feqn /. fCalc -> fCalc2, initcs}, vars, {t, 0, 1}];]

So my question is, how to I trick Mathematica into waiting to evaluate the NDSolve until after giving values to the variables, and without having to repeatedly evaluate the fCalc function. There is an answer for solving for a vector system at this question, but I can't write my whole system in terms of a derivative of a vector as in that case.


My actual system is much more complicated (see the initial version of this question if you want to see), but I definitely need the numerical restriction on fCalc.





Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.