Skip to main content

list manipulation - Equivalent Nested Loop Structure


Consider the following examples:


Flatten @ Table[ f[a, b, c], {a, 1, 3}, {b, 1, 3}, {c, 1, 3}] ==
f @@@ Tuples[ Range[3], 3]

Flatten @ Table[ If[ a != b != c, f[a, b, c], Unevaluated[]],
{a, 1, 3}, {b, 1, 3}, {c, 1, 3}] ==
f @@@ Permutations[ Range[3], {3}]


Flatten @ Table[ f[a, b, c], {a, 1, 5}, {b, a + 1, 5}, {c, b + 1, 5}] ==
f @@@ Subsets[ Range[5], {3}]


True
True
True

Is there a similar built-in function performing this:



Flatten @ Table[ f[a, b, c], {a, 1, 5}, {b, a, 5}, {c, b, 5}]

in a simpler way?



Answer



Here a two more ways, neither of them built-in.
f @@ (# - {0,1,2})& /@ Subsets[Range@7,{3}]
f @@@ Transpose[Transpose@Subsets[Range@7,{3}] - {0,1,2}]


EDIT - The question is related to a long and somewhat tangled MathGroup thread generating submultisets with repeated elements. "sms" below stands for for "submultisets".


sms[n_, k_, f_:List] := With[{i = Table[Unique[],{k}]}, Flatten[Table[f@@i,
Evaluate[Sequence@@Transpose@{i,Prepend[Most@i,1],Table[n,{k}]}]],k-1]]


sms[5, 3]
sms[5, 3, f]


{{1,1,1}, {1,1,2}, {1,1,3}, {1,1,4}, {1,1,5}, {1,2,2}, {1,2,3}, {1,2,4}, {1,2,5}, {1,3,3}, {1,3,4}, {1,3,5}, {1,4,4}, {1,4,5}, {1,5,5}, {2,2,2}, {2,2,3}, {2,2,4}, {2,2,5}, {2,3,3}, {2,3,4}, {2,3,5}, {2,4,4}, {2,4,5}, {2,5,5}, {3,3,3}, {3,3,4}, {3,3,5}, {3,4,4}, {3,4,5}, {3,5,5}, {4,4,4}, {4,4,5}, {4,5,5}, {5,5,5}}


{f[1,1,1], f[1,1,2], f[1,1,3], f[1,1,4], f[1,1,5], f[1,2,2], f[1,2,3], f[1,2,4], f[1,2,5], f[1,3,3], f[1,3,4], f[1,3,5], f[1,4,4], f[1,4,5], f[1,5,5], f[2,2,2], f[2,2,3], f[2,2,4], f[2,2,5], f[2,3,3], f[2,3,4], f[2,3,5], f[2,4,4], f[2,4,5], f[2,5,5], f[3,3,3], f[3,3,4], f[3,3,5], f[3,4,4], f[3,4,5], f[3,5,5], f[4,4,4], f[4,4,5], f[4,5,5], f[5,5,5]}



sms[data_List, k_, f_:List] := With[{i = Table[Unique[],{k}]}, Flatten[Table[f@@data[[i]],
Evaluate[Sequence@@Transpose@{i,Prepend[Most@i,1],Table[Length@data,{k}]}]],k-1]]


data = {a,b,c,d,e};
sms[data, 3]
sms[data, 3, f]


{{a,a,a}, {a,a,b}, {a,a,c}, {a,a,d}, {a,a,e}, {a,b,b}, {a,b,c}, {a,b,d}, {a,b,e}, {a,c,c}, {a,c,d}, {a,c,e}, {a,d,d}, {a,d,e}, {a,e,e}, {b,b,b}, {b,b,c}, {b,b,d}, {b,b,e}, {b,c,c}, {b,c,d}, {b,c,e}, {b,d,d}, {b,d,e}, {b,e,e}, {c,c,c}, {c,c,d}, {c,c,e}, {c,d,d}, {c,d,e}, {c,e,e}, {d,d,d}, {d,d,e}, {d,e,e}, {e,e,e}}


{f[a,a,a], f[a,a,b], f[a,a,c], f[a,a,d], f[a,a,e], f[a,b,b], f[a,b,c], f[a,b,d], f[a,b,e], f[a,c,c], f[a,c,d], f[a,c,e], f[a,d,d], f[a,d,e], f[a,e,e], f[b,b,b], f[b,b,c], f[b,b,d], f[b,b,e], f[b,c,c], f[b,c,d], f[b,c,e], f[b,d,d], f[b,d,e], f[b,e,e], f[c,c,c], f[c,c,d], f[c,c,e], f[c,d,d], f[c,d,e], f[c,e,e], f[d,d,d], f[d,d,e], f[d,e,e], f[e,e,e]}



Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...