Skip to main content

Alternatives ordering affects pattern matching in Cases?


Given


expr = f[x, g[y], z]

In the following query, the pattern h_[__, c_] appears as last slot in Alternatives:


Cases[expr, (h_[c_] | h_[c_, __] | h_[__, c_, __] | h_[__, c_]) :> 
h -> c, {0, Infinity}]


Gives


{g -> y, f -> x}

Ie, "f[__,z]" is not matched but is matched when the pattern is rotated to the first slot:


Cases[expr, (h_[__, c_] | h_[c_] | h_[c_, __] | h_[__, c_, __]) :> 
h -> c, {0, Infinity}]

Which gives:


{g -> y, f -> z}


Souldn't Alternatives be commutative? Apparentely only the first match per level is returned. Is there a method to return x, y and z containing patterns?



Answer




  • Patterns in Alternatives are tried in order

  • Only the first pattern that matches is "applied" to the expression.

  • Cases does not support multiple patterns outside of Alternatives.


I suppose it could be interesting to debate that design decision but nevertheless that's the way it works at this time.


You could of course search with multiple passes:



expr = f[x, g[y], z]
pat = h_[c_] | h_[c_, __] | h_[__, c_, __] | h_[__, c_];

Join @@ (Cases[expr, # :> h -> c, {0, -1}] & /@ List @@ pat)


{g -> y, f -> x, f -> g[y], f -> z}

Or using ReplaceList and Level:


rules = # :> h -> c & /@ List @@ pat

Join @@ (ReplaceList[#, rules] & /@ Level[expr, {0, -1}])

Since neither of these is efficient you could subvert the normal evaluation by using side-effects, e.g. with Condition:


Module[{f},
f[pat] := 1 /; Sow[h -> c];
Reap[Scan[f, expr, {0, -1}]][[2, 1]]
]


{g -> y, f -> x, f -> g[y], f -> z}


Or more cleanly, though perhaps rather enigmatically, using Cases itself:


Reap[Cases[expr, pat :> 1 /; Sow[h -> c], {0, -1}];][[2, 1]]


{g -> y, f -> x, f -> g[y], f -> z}

Finally, if traversal order is irrelevant:


Reap[expr /. pat :> 1 /; Sow[h -> c]][[2, 1]]



{f -> x, f -> g[y], f -> z, g -> y}



A note regarding another ramification of Alternatives is here:





NOTE: It looks like my assumptions about efficiency were wrong, and the multi-pass method may be more efficient than the rest. I need to explore this further but I have neither the time nor the interest right now.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

Is there a way to do conditional matrix loop using 'continue'

I have the following: n = 3; m = 5; ww = RandomReal[{0, 0.1}, {n, n}]; uu = RandomReal[{0, 1}, {m, n}]; pp = RandomReal[{0, 1}, {n, n}]; ss = RandomInteger[{0, 5}, {m, n}]; Grid[{{"ww", "uu", "pp", "ss"}, {ww // TableForm, uu // TableForm, pp // TableForm, ss // TableForm}}, Spacings -> {5, 2}, Dividers -> All] where I would like to look at every element of matrix ss and produce a matrix tt , with zeroes at the locations in ss which have zeroes, and in all other positions do the following: tt = (-1/Subscript[ww, m]) Log[(1 - uu)/(Subscript[pp, m - 1])], where Subscript[ww, m] is the value at index of ww matrix and where Subscript[pp, m - 1] is the value at index-1 of pp matrix. So for example if the first value ever read from matrix ss happens to be 2, then value taken from matrix ww would be from the row 2, but from pp would be from row 1. Also how to tell difference between a 0 as a valid value from within the matrix elemen...