Skip to main content

plotting - Do I have to code each case of this Grid full of plots separately?


I have written some custom functions to draw multi-panel graphs like this one: enter image description here


It's done by passing a matrix of (custom) plotting functions to a MultiPanelGraph function, which pulls apart the head, argument and options of those plots, adds a few of its own, and then puts it all together. There is also some funkiness to deal with plot labels and footnotes, but I've removed these from the code below for simplicity. The PanelHeightFactor type options are custom options to the custom functions for the individual plots. Likewise the MultiPanel option tells the custom functions for the individual plots to, for example, turn off ticks and tick marks on particular sub-plots so that they all fit together neatly as shown in the picture above, and to turn the PlotLabel into a panel label inside the plot frame using Prolog.


Attributes[MultiPanelGraph]={HoldFirst};

MultiPanelGraph[{{l_[largs__,lopts___Rule], r_[rargs__,ropts___Rule]}}, 
 mpopts:OptionsPattern[{MultiPanelGraph,myLineGraph}]] := 
Module[{ (* there was some stuff here *)},With[{
    wl = PanelWidthFactor /.{lopts}/.{PanelWidthFactor->1/2},
    wr = PanelWidthFactor /.{ropts}/.{PanelWidthFactor->1/2},
    Grid[{{l @@ Join[{largs},{lopts}, 
       {MultiPanel-> {All,Left},PanelHeightFactor->1,PanelWidthFactor->wl,
        ImageMargins->0}],
          r @@ Join[{rargs},{ropts}, 
       {MultiPanel->{All,Right},PanelHeightFactor->1,

        PanelWidthFactor->wr,ImageMargins->0}]}},
     Sequence @@ FilterRules[Join[{mpopts},{lopts},{ropts}],Grid],
    Spacings -> {0,0} , ItemSize -> {{4.8+42.*wl, 4.+42.*wr},Full}, Alignment -> Left]

It works fine (aside from some issues to do with ImageSize being measured in points and ItemSize being measured in x-heights or some silly thing - a topic for another question), but I would have to code every single case - 2 by 1, 2 by 2, 3 by 4, whatever else some manager decides he or she wants - separately. Doable, but tedious.


I can imagine capturing the dimensions of the grid to get the appropriate default PanelWidthFactor and PanelHeightFactor, but beyond that I don’t know if there is a neat way to capture all the possible cases in one definition of the function. Does anyone have any suggestions for coding this in a way that doesn’t require each separate case to be coded to match separately? It would have to handle telling the subplot which ticks to use depending on its position.


EDIT: A couple of additional business requirements that might be useful to know:



  • It's essential for the plot frame to be the same width and height, regardless of how many panels there are, unless this is explicitly overridden (in my code, by having an explicit PanelHeightFactor or PanelWidthFactor option in the code for the subgraph).

  • Panels can be of dated data (DateListPlot or a custom DateListBarChart) or undated data (ListPlot, BarChart), but never both in the same chart.


  • The subplots will have some options (namely footnotes and source notes) that need to be captured and merged to be shown down the bottom of the main plot.



Answer



The nub of the answer turned out to rest on solutions to this question, particularly Heike's.


The trick is to Map Hold onto the subplots at the required level, and also to extract the Head of the plotting function in the right way. Heike's answer to that question gives a simple version of the solution. Below is a cutdown version of my actual code, where myLineGraph etc are custom functions that take MultiPanel, PanelHeightFactor and PanelWidthFactor options that determine the size of the graph panel relative to a standard dimension, and which sets of frame labels should show on the graph.


MultiPanelGraph[gs_?MatrixQ,mpopts:OptionsPattern[{MultiPanelGraph,myLineGraph,myBarGraph,myUndatedLineGraph}]]:=
 Module[{nr,nc, gsheld,subrules,subargs,subplots, pwfs,phfs,mph = OptionValue[Title]},
    {nr, nc} = Dimensions[gs];
    gsheld = Map[Hold, Unevaluated[gs], {2}];
    subrules = Table[Cases[gsheld[[i,j]],_Rule,{2}],{i, nr},{j, nc}];         

      (* collects all the options explicitly set for each sub-plot *)
    subargs =  Table[Cases[gsheld[[i,j]],Except[_Rule],{2}],{i, nr},{j, nc}]; 
      (* collects all the non-option arguments for each sub-plot *)
    pwfs = Flatten@Table[PanelWidthFactor /.{subrules[[1,j]]}/.{PanelWidthFactor->1/nc},{j, nc}]; 
      (* assume only options specified in first row graphs override default PWF *)
    phfs = Flatten@Table[PanelHeightFactor /.{subrules[[i,1]]}/.{PanelHeightFactor->1/nr},{i, nr}];  
     (* assume only options specified in first row graphs override default PHF *)
    subplots = Table[gsheld[[i, j, 1, 0]]@@ Join[{Flatten[subargs[[i,j]],1]},{subrules[[i,j]]}, 
       {MultiPanel-> {Switch[i,1,If[nr==1,All,Top],nr,Bottom,_,Middle],
        Switch[j,1,If[nc==1,All,Left],nc,Right,_,Center]}, 

     (* determines panel side - top, left etc. Captures case 
      where only one row or one column - NB 1,1 will not look like a one-panel graph *)
        PanelHeightFactor->phfs[[i]],PanelWidthFactor->pwfs[[j]],ImageMargins->0}],
         {i,nr},{j,nc}];  
      (* put head and args of subplots together with other arguments 
      that need to be passed to them *)
        Grid[subplots, Alignment->Left, Spacings->{0,0}, ItemSize-> {Full, Full}]
 ]

Comments

Post a Comment

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]
Post a Comment
Read more

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....
Post a Comment
Read more