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Plotting results of NIntegrate with variable integration limit


I have tried to use NIntegrate with variable limits and compute the following


(*parameters*)
Ωm = 1.0;
ΩΛ = 0.0;
Ωk =
1 - Ωm - ΩΛ;

(*Integral with variable limits*)
A[a_?NumericQ] := (5 Ωm)/

2 ((Ωm a^-3 + ΩΛ + \
Ωk a^-2)^(1/2)) NIntegrate[
1/(x (Ωm x^-3 + ΩΛ + \
Ωk x^-2)^(1/2))^3, {x, 10^-7, a}];

(*plotting data giving values to `a`*)
Plot2 = ListLinePlot[A[a], {a, 0.1, 1}, PlotRange -> {0, 1},
AxesOrigin -> {0, 0}]

I supposed that A[a] was "free" until ListLinePlot give values to a, but no.



Another problem is that NIntegrate is not working here, the plot at the end looks like y=x.



Answer



You are almost there. You only missed to create the list that you want to plot. Here are your definitions:


  (*parameters*)
Ωm = 1.0;
ΩΛ = 0.0;
Ωk =
1 - Ωm - ΩΛ;

(*Integral with variable limits*)

A[a_?NumericQ] := (5 Ωm)/
2 ((Ωm a^-3 + ΩΛ + \
Ωk a^-2)^(1/2)) NIntegrate[
1/(x (Ωm x^-3 + ΩΛ + \
Ωk x^-2)^(1/2))^3, {x, 10^-7, a}];

Here is the list with the structure {a, int}:


  lst = Table[{a, A[a]}, {a, 0.1, 1, 0.05}]

and then one should plot the list, rather than the function:



 Plot2 = ListLinePlot[lst, PlotRange -> {0, 1}, AxesOrigin -> {0, 0}]

which returns the image below:


enter image description here


You could also do it as follows skipping the list stage:


Plot[A[a], {a, 0.1, 1}, PlotRange -> {0, 1}, AxesOrigin -> {0, 0}]

The returned image is identical to the one above.


Have fun!


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