Skip to main content

calculus and analysis - Problem with Integrate with Piecewise and PrincipalValue


Bug introduced in 8.0.4 or earlier and persisting through 11.3



In the course of developing an alternative solution for question 127301,


With,


$Version
(* "11.0.0 for Microsoft Windows (64-bit) (July 28, 2016)" *)

I attempted to perform the integral,


um = -(2/3) - 2/(3 (-1 + u)) - (2 u)/3 + u^2/3;
up = -(10/3) - 2/(3 (-1 + u)) + (8 u)/3 - u^2/3;
sv = Piecewise[{{um, u <= 1}, {up, u > 1}}];
Integrate[sv, {u, 0, 2}, PrincipalValue -> True]


but received the error message,



Integrate: Integral of ... does not converge on {0,2}.



Separating the term, -(2/(3 (-1 + u))), does not help.


sv1 = Piecewise[{{um + 2/(3 (-1 + u)), u <= 1}, {up + 2/(3 (-1 + u)), u > 1}}];
Integrate[sv1 - 2/(3 (-1 + u)), {u, 0, 2}, PrincipalValue -> True]

yielding the same error message. Yet,



Integrate[sv1, {u, 0, 2}] - 
Integrate[2/(3 (-1 + u)), {u, 0, 2}, PrincipalValue -> True]
(* -1 *)

does work. (The second integral equals 0, incidentally.) Is this a bug, or am I missing something? Thanks.


(Note that 10.4.1 produces the same results.)


Addendum: Workaround


Slightly shifting the Piecewise boundary at u = 1 so that the singular point lies within one or the other segment gives an accurate result. For instance, redefining sv as


sv = Piecewise[{{um, u <= 1 + 10^-10}, {up, u > 1 + 10^-10}}];


allows sv to be integrated by Integrate.


Integrate[sv, {u, 0, 2}, PrincipalValue -> True] // FullSimplify
(* -(4500000000000000000044999999999/4500000000000000000000000000000) *)

which is 1. to 20 significant figures. That this occurs is consistent with the suggestion by MichaelE2 that Integrate integrates each segment of Piecewise independently and, therefore, cannot handle singularities at the boundary between two segments. Nonetheless, I believe that it should be able to. Failing that, the documentation should describe this limitation.



Answer



I think this is a bug, because if we transform the Piecewise function into a combination of UnitStep (which is mathematically equivalent to the original function of course), Integrate integrates without difficulty:


um = -(2/3) - 2/(3 (-1 + u)) - (2 u)/3 + u^2/3;
up = -(10/3) - 2/(3 (-1 + u)) + (8 u)/3 - u^2/3;
sv = Simplify`PWToUnitStep@Piecewise[{{um, u <= 1}, {up, u > 1}}];

Integrate[sv, {u, 0, 2}, PrincipalValue -> True]
(* -1 *)

Tested on v9.0.1 and v11.2.


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...