Skip to main content

list manipulation - How to create a version of FixedPointList for asymptotically periodic functions?



I need to efficiently generate a bunch of bifurcation diagrams. A simple familiar example illustrates the efficiency problems I'm running into:


bifurcation


ListPlot[Catenate[Table[{x, #} & /@ DeleteDuplicates[
FixedPointList[#^2 + x &, Evaluate[Nest[#^2 + x &, x, 999]],100]],
{x, -2, .25, .0001}]], PlotStyle -> PointSize[Tiny], PlotRange -> All]

This method is a bit inefficient.


FixedPointList[] does nothing unless the series z->(z^2+x) becomes 1-periodic (to within machine precision) within 999 cycles. Some numbers like -.75 and -1.25 still don't quite reach their asymptotes after 999 cycles, which is why those bifurcations look soft on my diagram above. But then for some numbers like the neighborhoods of -1, 999 is ridiculous overkill. DeleteDuplicates cleans up the 100-fold redundancy I wish I hadn't had to generate in the first place.


All these problems would be solved if I had a function similiar-ish to FixedPointList that worked on periodic functions. But I don't know how to write a function that takes a function as an input. Here's my best effort below with a hard-wired function z->(z^2+x), but it's so sloooooow it's worse than the one-line code above, but I'd bet that's a problem with my coding. I've had fingers wagged at me for using Do Loops, but I don't know how to get by without one in this case.


My code below returns a 3-element result:



{List become periodic True/False, Element in list that would match the next element in the list, the result list}


FixedPeriodList[x_, maxLength_] := Module[{ret},
ret = 0;
ans = ConstantArray[0, maxLength];
ans[[1]] = x;
Do[ (*MMa jocks scoff at Do loops!*)
ans[[i]] = ans[[i - 1]]^2 + x;
If[ContainsAny[Part[ans, 1 ;; i - 1], {ans[[i]]}],
ret = {True, Position[Part[ans, 1 ;; i - 1], ans[[i]]][[1, 1]],Part[ans, 1 ;; i - 1]};
Break[]], {i, 2, maxLength}];

If[ret == 0, ret = {False, 1, ans}];
ret];

a=FixedPeriodList[-1.754, 10000]

Part[#[[3]], #[[2]] ;; Length[#[[3]]]] &@ a

(* {True, 34, {-1.754, 1.32252, -0.00495143, -1.75398, 1.32243, -0.00517891, -1.75397, 1.32242, -0.00520029, -1.75397, 1.32242, -0.00520234, -1.75397, 1.32242, -0.00520254, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256, -1.75397, 1.32242, -0.00520256}}


{-1.75397, 1.32242, -0.00520256} *)


How can we create a FixedPeriodList that works more efficiently? And with the function specifiable like in FixedPointList?





Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.